已知y等于6加2
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应该是x^2-2x+y^2+6y+10=0配方:x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0得x=1y=-3所以x+y=-2
x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0(x-1)^2=0x-1=0x=1(y+3)^2=0y+3=0y=-3x+y=1-3=-2
x^2+2x+y^2-6y+10=0=(x^2+2x+1)+(y^2-6y+9)=0=(x+1)^2+(y^2-6y+3^2)=0=(x+1)^2+(y-3)^2=0x=-1y=3xy=-3
(x+y)/2=(y+z)/3=(z+x)/4整理3x+3y=2y+2z4x+4y=2x+2z4y+4z=3z+3x化简的y=1/3xz=5/3x代入2x+4y+6z=120得x=9因而求的y=3z=
x^2-2x+y^2+6y+10=0x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0x-1=0,y+3=0x=1,y=-3(x-y)/(x+y)=4/(-2)=-2
3x^2+2xy+y^2-6x-6y+9=0(x+y)^2-6(x+y)+9=0(x+y-3)^2=0x+y=3
x^2+y^2+2x-6y+10=0(x^2+2x+1)+(y^2-6y+9)=0(x+1)^2+(y-3)^2=0平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立所以两个都等于0所
原等式可化为:x²-2xy+y²+6(x-y)+9+y²=0即:(x-y)²+6(x-y)+9+y²=0(x-y+3)²+y²=0
x=1,y=-3再问:过程再答:化简一下就得到方程(x-1)2+(y+3)2=0.这里的2表示平方啊,不知道怎么打平方。很明显只有x=1,y=-3才满足啊。
x²+y²+4x-6y+13=0(x+2)²+(y-3)²=0x+2=0、y-3=0x=-2、y=3
1-4x+6y=1-2(2x-3y)=1-6=-5
y=6-xy²=2+7x所以36-12x+x²=2+7xx²-19x+34=0(x-2)(x-17)=0x=2,x=17y=6-x所以x=2,y=4x=17,y=-11
7再答:要过程吗再问:不用再答:有好评吗
问题求什么?再问:求x加y的值再答:x^2-2x+1+y^2-6y+9=0(x-1)^2+(y-3)^2=0x=1y=32x+3y=11
√(x-2)+(y+3)²=0根号和平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.所以两个都等于0所以x-2=0,y+3=0x=2,y=-3x+y=-1(x+y)^20
1.设y=k(x+2),由题得-6=k(1+2)k=-2所以y=-2(x+2),即2x+y+4=02.将(a,2)代入方程,得2a+2+4=0a=-3
x^2减6xy加9y等于0.则x:y等于_3:1___.
x^2+y^2+2x-6y+10=0(x+1)^2+(y-3)^2=0所以x+1=0,y-3=0所以x=-1,y=3所以x+y=-1+3=2
xy分之【x加y】等于2分之一xy=2(x+y)【xy加x加y】分之xy=2(x+y)/[2(x+y)+x+y]=2(x+y)/[3(x+y)]=2/3