已知直线y 3分之根号3x 3-搜答案-大师作文网

x=log2(y)则X1+2X2+3X3=log2(y1)+2log2(y2)+3log2(y3)=log2(y1)+log2(y2^2)+log2(y3^3)=log2(y1y2^2y3^3)=1所

原式=x3-2y3-3x2y-3x3+3y3+7x2y=-2x3+y3+4x2y

很高兴喂你解答!原式=4√[(x^2+xy+y^2)/(x-y)*1/2√[(x^2-xy+y^2)/(x+y)*3√(x^3+y^3)=6√[(x^2+xy+y^2)/(x-y)*√[(x^2-xy

因为A+B+C=x3-2y3+3x2y+xy2-3xy+4+y3-x3-4x2y-3xy-3xy2+3+y3+x2y+2xy2+6xy-6=1，所以，对于x、y、z的任何值A+B+C是常数．

∵x+y=1，∴x3+y3+3xy=（x+y）（x2-xy+y2）+3xy=x2+y2+2xy=（x+y）2=1．

要使二次根式有意义,x^2=9,x=3,-3x=3,y=0,x+y有平方根,立方根.x=-3,y=3/5,x+y有平方根,立方根

由(x+y+z)2-(x2+y2+z2)可得xy+xz+yz=-5x3+y3+z3-3xyz=（x+y+z)(x2+y2+z2-xy-yz-zx）可得xyz=14再问：谢谢，我看一下其他的答案在采纳再

x3+3xy+y3=（x+y）（x2-xy+y2）+3xy，=（x2-xy+y2）+3xy，=（x+y）2-3xy+3xy，=1．

A+B+C=（x3+3x2y-5xy2+6y3-1）+（y3+2xy2+x2y-2x3+2）+（x3-4x2y+3xy2-7y3+1）=（1+1-2）x3+（3+1-4）x2y+（-5+2+3）xy2

(x+y)³=x³+y³+3x²y+3xy².记忆方法：各立方,然后3x方y,3xy方(x+y)³=x³-y³-3x&#

已知点(-2,y1)(-1,y2)(1,y3)都在直线y=3分之1x+b,因为k=3分之1＞0所以函数是增函数又-2

x+y=1(x+y)^2=x^2+2xy+y^2=1(x+y)^3=x^3+y^3+3xy(x+y)=1而x^3+y^3=1/3,代入得：3xy=2/3xy=2/9由于x=1-y;故代入xy=2/9;

这是要立方和公式,x^3+y^3+3xy=(x+y)(x^2-xy+y^2)+3xy=x^2-xy+y^2+3xy=(x+y)^2=1

A-B=(x3+2y3-xy2)-(﹣y3+x3+2xy2)=x³+2y³-xy²+y³-x³-2xy²=3y³-3xy²

27.已知x=1.25,y=-0.64时,求[(x+y)3-(x3+y3)]÷(x+y)的值.[(x+y)^33-(x^3+y^3)]÷(x+y)解,得：==(x+y)^3*1/(x+y)-(x+y)

设两直线夹角为θ,l1的倾角为α,l2的倾角为β.则:tanα=(y2-y2)/(x2-x1)tanβ=(y4-y3)/(x4-x3)根据两直线夹角公式得:tanθ=(|tanα-tanβ|)/(1+

2.

x^3+y^3+z^3-3xyz=[(x+y)^3-3x^2y-3xy^2]+z^3-3xyz=[(x+y)^3+z^3]-(3x^2y+3xy^2+3xyz)=(x+y+z)[(x+y)^2-(x+

x3+3xy-y3=(x-y)(x^2+y^2+xy)+3xy=-x^2-y^2+2xy=-(x-y)^2=-1