A B问题C语言 第一行:输入一个整数n. 第二行:输入n个正整数.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/30 01:43:37
这设计到计算机的数值表示问题,一般32位的计算机用unsignedlonglong最大能表示的也只到18446744073709551615,所以超过20位做运算时就因为计算机不能表示而出错了.对于这
#includevoidmain(){inti,N,sum;while(scanf("%d",&N)){sum=0;for(i=1;i
#includeintmain(){inti,j,a,b;scanf("%d\n",i);printf("pleaseinputnumber\n");scanf("%d\t",a);b=a;for(j
#include voidmain(){inti;intj[6];inta;intsum=0;for(i=0;i
#includemain(){intm,n,s=2,j=0;registerinti;printf("pleaseinputanumber:n=");scanf("%d",&n);while
if(s[i][0]=='0')“'0'”只是一个字符去掉看看.再问:这样我连编译都通不过
输入两个正整数m和n,求其最大公约数和最小公倍数.main(){longm,n,i=1,j,s;scanf("%ld,%ld",&m,&n);for(;i
#include<stdio.h>int main(){\x09int n,num,i,sum=0,j,k,l,m;\x09scanf("%d",&
#include <stdio.h>void main (){ int a[10]; int i,k=0,n,min,
#includeintmain(){inti,max,min,n,a[105];scanf("%d",&n);scanf("%d",&a[1]);max=a[1];min=a[1];for(i
#include"stdio.h"#include"iostream"intmain(){inti,x,y=1;scanf("%d",&x);for(i=2;i
#include<stdio.h>#include<string.h>#include "math.h"void fun(){\x09p
感觉像是ACM的题.N
结构体+动态内存分配#include "stdio.h"#include "stdlib.h"struct Co{ &n
#include#includeintmain(){chars[10]="ABCDE";printf("请输入一个字符和一个数字,以逗号分隔:");inta;charb;scanf("%c,%d",&
#include#definen3intmain(){inti,j;for(i=0;i再问:--第一行是1*第二行是3*第三行是6*第四行是9*再答:#include#definen4//输出4+1=
#includevoidmain(){inti,j,k,m,n;charch;printf("Entern:\n");scanf("%d",&n);for(i=1;ii;k--)putchar('')
#includeintmain(void){inti,j,n;printf("Plzinputaint:");scanf("%d",&n);for(i=1;i再问:abs是什么再答:取绝对值
#include"stdio.h"#include"math.h"intmain(void){intcount,i,m,n,sum;intrepeat,ri;intprime(intm);scanf(
#includeintmain(){inti,j,n;charc='A';scanf("%d",&n);for(i=0;i