微积分X^3sin^2x x^4 2x^2 1 (-5.5)
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∫sin^3(x)cos^2(x)dx=∫sin^2(x)cos^2(x)sin(x)dx=-∫sin^2(x)cos^2(x)dcos(x)=∫[cos^2(x)-1]cos^2(x)dcos(x)
sin^2(x)cos^4(x)=1/4*sin²2xcos²x=1/4*(1-cos4x)/2*(1+cos2x)/2=1/16*(1+cos2x-cos4x-cos2xcos4
我来给你做吧,首先被积函数分子分母同除以9^x变形,看下图吧
-1/4cos4x+C
伤心地哭开心地笑兴奋地说高兴地唱坚持地做跑跳呆呆地想傻傻地看
用公式a³+b³=(a+b)(a²-ab+b²)cos^6x+sin^6x=(cos²x)³+(sin²x)³=(cos
原式=1/2∫sin²(2x+1)cos(2x+1)d(2x+1)=1/2∫sin²(2x+1)dsin(2x+1)=1/6*sin³(2x+1)+C
4^sin(3x^2+8)的导数=4^sin(3x^2+8)*ln4*【sin(3x^2+8)的导数】=4^sin(3x^2+8)*2ln2*cos(3x^2+8)*(6x)
方程左边1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20)对分母因式分解得1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(
-(3/2π)cos(2πX/3)+C(常数)
x=0:0.1:2*pi;s=2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x);plot(x,s)
1.将分母变为sin2x即原式为∫[(4cos2x/sin^2(2x))]dx2.进行换元即2x变为t,原式变为∫[(2cos2x/sin^2t)]dt.3继续换元,可观察到(sint)'=cost.
1.∫sin(πx)cos(πx)dx=∫sin(2πx)/2dx=-cos(2πx)/4π+C2.∫0~3|x^2-4|dx=∫0~2|x^2-4|dx+∫2~3|x^2-4|dx=∫0~2(4-x
两边同时对x微分得dcos(x^2+y)=dx,即-sin(x^2+y)(2dx+dy)=dx,将dy移过去,变形得到-(1+2sin(x^2+y))dx/sin(x^2+y)=dy
lim(x→0)[(3sinx+x^2*cos1/X)/(1+cosx)*In(1+x)]=lim(x→0)1/(1+cosx)lim(x→0)[(3sinx+x^2*cos1/X)/In(1+x)]
sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2xcos^2x+cos^4x-3sin^2xcos^2x=(sin^2x+cos^2x)^2-3sin^2xcos^2x
xx+yy+4x-6y+13=0整理得:(x+2)^2+(y-3)^2=0那么只有(x+2)=0(y-3)=0x=-2y=3(x^2-2x)/(x^2+3y^2)=(4+4)/(4+3*9)=8/31
(1)原式=1/2∫sin√(x²+4)/(√(x²+4)d(x²+4)=-∫sin√(x²+4)d√(x²+4)=cos√(x²+4)+C
sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2xcos^2x+cos^4x-3sin^2xcos^2x=(sin^2x+cos^2x)^2-3sin^2xcos^2x