a的平方x-y y-x
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即比较a和a²的大小a²-a
(x-y)(x+y)(xx-yy)=(x^2-y^2)(x^2-y^2)=x^4-2x^2y^2+y^4
x²-7x+12=(x-3)(x-4)x²+3x-40=(x+8)(x-5)
是不是(x-a)/(x-a)^20所以乘过去,x-a
x^2+y^2-2x+y+k=0x^2-2x+1-1+y^2+y+1/4-1/4+k=0(x-1)^2+(y+1/2)^2-5/4+k=0(x-1)^2+(y-1/2)^2=5/4-k5/4-k>0k
令x=asin(t)就做出来了...答案是-根号下a平方-x平方再问:能详细写下积分过程吗?谢谢。再答:换元积分,微积分里有的~
先将96=3*2*2*2*2*2然后组合成12*8=96xxy+yyx=xy(x+y)=12*8=2*6*(2+6)=12*8=96x=2,y=6xx+yy=2*2+6*6=4+36=40
xy(x-y)-x(x-y)平方=(x-y)[xy-x(x-y)]=(x-y)[2xy-x^2]=(x-y)*x(2x-y)-a平方+1.9b平方=(b根号1.9+a)(b根号1.9-a)-12xy+
XX-YY/(X-Y)(X-Y)=(x^2-y^2)/(x-y)(x-y)=(x+y)(x-y)/(x-y)(x-y)=(x+y)/(x-y)
因xx-yy=(x-y)(x+y)所以x-y≠0x+y≠0否则xx-yy=0集合b中就有两个0于是xy=0所以x=0或y=0若y=0,则x-y=x+y=xA中有两个x,不成立故y≠0x=0这样x-y=
题目应该是a(x²-2x)²-2a(x²-2x)-3a吧?=a[(x²-2x)²-2(x²-2x)-3]=a(x²-2x-3)(x
xx'+yy'+zz'可以由前面的推导过来.|a|=√(x^2+y^2+z^2)|b|=√(x'^2+y'^2+z'^2)|c|=√((x-x')^2+(y-y')^2+(z-z')^2)cosθ=|
2/9再问:过程,谢谢再答:由题目得y/x=2/3xy/xx+yy-yy/xx-yy=y/x-(y/x)²=2/3-4/9=2/9
x^2-x+1/4-1/4+a
您好:x的平方-2ax+a的平方=x-a(x-a)²=x-a(x-a)²-(x-a)=0(x-a)(x-a-1)=0x1=ax2=a+1如果本题有什么不明白可以追问,如果满意记得采
(4x+3y-1)²+|2x-y+7|=0|2x-y+7|>=0所以只能(4x+3y-1)²=0|2x-y+7|=0即4x+3y-1=02x-y+7=0解得x=-2y=3
xx+yy+4x-6y+13=0整理得:(x+2)^2+(y-3)^2=0那么只有(x+2)=0(y-3)=0x=-2y=3(x^2-2x)/(x^2+3y^2)=(4+4)/(4+3*9)=8/31
a(x²+2xy+y²)-b(x²-y²)=a(x+y)²-b(x+y)(x-y)=(x+y)(ax+ay-bx+by)再问:你确定对吗?和我已开始算
这个第一道应该是令y'=p然后y''=dp/dx的x*dp/dx=p*ln(p/x)然后解出p对P积分即可得到答案第二道也是令y'=p的y''=dp/dx*dy/dy=dp/dy*dy/dx=p*dp
xx-yy-x-y=(x^2-y^2)-(x+y)=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)