把分式2x-3y分之2x的xy扩大的五倍
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2/xy=2(y-x)/xy(y-x)3y/(xy-x^2)=3y^2/xy(y-x)如果不懂,请追问,祝学习愉快!
1/x+1/y=2则(2x+3xy+2y)/(x-xy+y)分子分母同除以xy=(2/x+2/y+3)/(1/x+1/y-1)=(4+3)/(2-1)=7
由1/x-1/y=3得(y-x)/xy=3题中的式子分子分母同时除以xy得(2/y+3-2/x)/(1/y-2-1/x),通分得【2(x-y)/xy+3】/【(x-y)/xy-2】代入得3/5
x/y=3=>x=3y原式=(9y²+2*3y*y-3y²)/(9y²-3y*y+y²)=12/7再问:能不能先化简,后代入?再答:可以是可以,x²+
2(x+3)分之x和(x-3)分之y的乘积
3/5因为1/x-1/y=3通分得y-x/xy=3所以x-y=-3xyx-2xy-y/2x+3xy-2y=2(x-y)+3xy/(x-y)-2xy=-6xy+3xy/-5xy=3/5还有什么不懂可以百
x²+3分之x-2y的值为0∵x²+3>0∴x-2y=0∴x=2yx²-y²分之x²-3xy-4y²=(x-4y)(x+y)/(x+y)(x
2xy/x+y中XY都扩大3倍.则原式=2*3X*3Y/(3X+3Y)=18XY/3(X+Y)=6XY/(X+Y)则分式的值是原来分式的值的__3倍___.
2x=-yy=-2xxy/(x^2-y^2)=x*(-2x)/[x^2-(-2x)^2]=-2x^2/[x^2+4x^2]=-2x^2/5x^2=-2/5
∵x/y=2/3∴设x=2t,y=3t∴(x²+3xy)/(x²+xy-6y²)=(4t²+3×2t×3t)/(4t²+2t×3t-6×9t²
正确答案是C.若是3x+4y=0的话,那分式出的就没意义了,考虑问题不要太偏激!那要是你所说,所有的分式分子都为0的话,还不用计算了呢!所以说你那是特殊情况,比如说,我说四边形的四个角是直角,你判断他
将分式(2x+3xy-2y)/(x-2xy-y)的分子分母同除以xy(因为xy不为零),(2x+3xy-2y)/(x-2xy-y)=(2/y+3-2/x)/(1/y-2-1/x)=[3-2(1/x-1
因为x=3y,所以原式=[(3y)²-3y·y+y²]分之[(3y)²+2·3y·y-3y²]=7y²分之12y²=7分之12
y-x=3xyx-y=-3xyx-2xy-y=-5xy2x+3xy-2y=2(x+y)+3xy=-6xy+3xy=-3xy分式x-2xy-y分之2x+3xy-2y=5/3
1/x-1/y=3(y-x)/xy=3y-x=3xy分式的分母=x-2xy-y=(x-y)-2xy=-5xy分子=2x+3xy-2y=2(x-y)+3xy=-3xy所以原式=3/5
(2x^2+3xy-2y^2)/(x^2+3xy+2y^2)={(2x-y)(x+2y)}/{(x+y)(x+2y)}=(2x-y)/(x+y)=02x-y=0
1/x+1/y=5(x+y)/x*y=5x+y=5*x*yx+2xy+y=x+y+2xy=5xy+2xy=7xy2x-3xy+2y=10xy-3xy=7xy(2x-3xy+2y)/(x+2xy+y)=
原式为2x^2/(x+y)xy都扩大3倍后2(3x)^2/(3x+3y)=18x^2/3(x+y)=6x^2/(x+y)