10 4x^3-9x^2 6x
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(3x+5)/(x+2)=[(3x+6)-1]/(x+2)=3-1/(x+2)后面都类似化简3-1/(x+2)+3-1/(x+9)=3-1/(x+6)+3-1/(x+5)1/(x+2)+1/(x+9)
|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|
设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y
再问:额、不懂再答: 再答:后面的看做一个整体再问:好的吧、谢谢大神再答:回来的话,请采纳再问:啊、突然明白了呢。。。
x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊
是9x-x³原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)=1/(x-3)-6/(x-3)(x+3)-(x
-2x>10x
中间错了原式=(x+2)/(x-3)(x+2)+2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)+2/(x-3)-(x+1)/(x-3)²=3/(x-3)-(x+1)/
原式=[x/x(x-3)](x+3)(x-3)=(x+3)(x-3)/(x-3)=x+3
x-60+3x=3x-63+7x4x-60=10x-634x-60+63=10x4x+3=10x3=10x-4x3=6xx=1/2
原式=(x+2)/(x+2)(x-3)-2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)-2/(x-3)-(x+1)/(x-3)²=-1/(x-3)-(x+1)/(x-
∫2^x*3^x/(9^x-4^x)dx=∫(2/3)^xdx/[1-(4/9)^x]=[ln(2/3)]^(-1)∫d[(2/3)^x]/{1-[(2/3)^x]^2}={[ln(2/3)]^(-1
(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]=1/(x-3)+2/(x-3)-
应该是-2x²,不是-3x²3x²-x=1原式=9x^4-3x³+15x³-5x²+3x²-7x+2001=3x²(3x
(x-1)(x-3)(x-5)(x-7)-9=(x-1)(x-7)(x-3)(x-5)-9=(x²-8x+7)(x²-8x+15)-9=(x²-8x)²+22(
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设x^3=a,则题目可变为下式:a^3+a^2+a-14=a^3-8+a^2+a-6=(a-2)(a^2+2a+4)+(a-2)(a+3)=(a-2)(a^2+2a+4+a+3)=(a-2)(a^2+
原式=[(2X-3)/X-X/X]/[(X+3)(X-3)/X]=[(2X-3-X)/X]/[(X+3)(X-3)/X]=[(X-3)/X]×[X/(X+3)(X-3)]=X(X-3)/[X(X+3)
(x^2-9)/(x+3)=(x+3)(x-3)(x+3)=(x+3)²(x-3)