c语言 10个元素的数组求平均值并输出比平均值大的数

是前n个元素么?main(){inti=n,sum=0;max=a[0];min=a[0];for(i=0;ia[i])?max:a[i];min=(min再问：输出的avg不是整数再答：哎呀，忘了这

#include"stdio.h"voidfun(int*s);intmain(){intnum[10]={1,2,4,2,5,6,7,2,34,67};fun(num);return0;}voidf

如果是纯C应该是下面这样的#include"stdio.h"intmain(){inta[5][5]={{1,2,4,4,5},{1,3,5,7,9},{2,4,6,8,10},{6,7,8,9,10

PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(

#inlcudevoidmain(){inta[6];inti,j,max=0,sum=0;doubleavg=0.0;printf("请输入六个数：\n");for(i=0;imax)max=a[i

祝你学习愉快!#include#defineN20intmain(){//声明被调用函数!voidmax(intb[],intn);voidmin(intb[],intn);voidaver(intb

#include#includemain(){inta[10],i,p=0;floatv=0.0,temp;for(i=0;i

#include "stdio.h"int main(){   float a[10]={0};  

#include#include#includeintmain(){srand((unsigned)time(0));intArray[10];inti=0;doublesum=0;intMax=-1

#include"stdio.h"#defineM3//在这里修改行数#defineN2//在这里修改列数main(){inta[M][N],i,j,k,l,max,f=0;floatave,s;pr

main(){inta[20],b[5],i;for(i=0;iscanf("%d",&a[i]);for(i=0;i{b[i]=(a[5*i]+a[5*i+1]+a[5*i+2]+a[5*i+3]+

#includevoidmain(){inti;intnum[10];intsum=0;for(i=0;i{scanf("%d",&num[i]);sum+=num[i];}floatavg=(flo

#include"stdio.h"voidmain(){inti,j;floatscore[10][4];floatmax=0,min=0,ave=0;for(i=0;i

#includeintmain(){inta[10];/*整形术组a,用于存放输入的10个整数*/inti,sum=0;/*sum用于存放10个整数的和*/floataverage;/*average

#include"stdio.h"voidmain(){inta[10],max,min,i,j,n,s=0;floatping=0,he=0;for(i=0;i

#include#includeintmain(){inta[10],n=0,i;for(i=1;i

main(){inti;doubleaverage=0;inta[10]={0};printf("请输入十个整数：");for(i=0;i0&&a[i]%2){average=(average+a[i

main(){inta[10],i,sum=0,x=0;/*初始化数值*/for(i=0;i

#include#includevoidmain(){inta[10];intsum=0;intbelow_ave=0;floatave=0;inti;printf("inputteninteger:

#include<stdio.h>int main(){\x05 int a[10];\x05 int i,j,val;\x05