c语言 输入两个整数m n 并求m除以n的余数k
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main(){inta,b,num1,num2,temp;printf("请输入两个正整数:\n");scanf("%d,%d",&num1,&num2);if(num1
#includeintmain(){floatf1,f2;inti1,i2;printf("输入2个数\n");scanf("%f,%f",&f1,&f2);printf("f1+f2=%.2f\n"
#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p
//#includevoidmain(){intm,n,i,min,max;printf("Pleaseinputm,n:\n");scanf("%d%d",&m,&n);min=mn?m:n;if(
三个空分别填:x/2k*(a&&b)printf按位与是将两个二进制数的对应位逐一地进行逻辑与操作.与的运算规则是两个数只要有一个为0,则其逻辑与的结果就为0举个例子你就明白了!定义:a=135,b=
#includeintmain(){inta,b,c;scanf("%d%d",&a,&b);c=a*b;while(a){if(a
下面用到了递归解决,不知楼主能否看懂.不懂用百度hi和我私聊我也很乐意.递归只是求最大公约数,通过最大公约数求最小公倍数.#include"stdio.h"voidmain(){intm,n,d,e;
#include#includeintmain(){intm,n,i,j,s;intarr[30][30];while(scanf("%d%d",&m,&n)!=EOF){for(i=0
假设是用a数组存放的数据intsum=0,i,num=0,average;for(i=0;i
除数为0时怎样做、不为0时怎样做,不用分支结构是处理不了这种问题的,亲.再问:大哥、、、、求解。。。我郁闷了。。。再答:汗,唯一的办法就是用分支结构,if(b=0){//输出错误信息printf("除
#includeintmain(){inta,b;floatc;printf("请输入两个整数和一个实数\n");scanf("%d%d%f",&a,&b,&c);c=a+b+c;printf("这三
#includevoidmain(){inta[10];inti,n=0;floatsum=0;for(i=0;i
#include#incluedvoidmain(){inta;intb;intc,d;a=1500,b=350;c=a/b;//商数d=a%b;//余数pritf("商数为:%d\n",c);pri
程序经过我用多组数据验证无错误,#includeintdigui(intt,intsum)//递归函数{if(t
#include#includeintmain(void){intn,sum=0,count=0,s;printf("输入一个整数:");scanf("%d",&n);while(n){s
print改成printf就可以了标准答案拿去吧除法进行的Int型的除法自己懂得#includeintmain(void){intnum1,num2;intx,y,z,k,j;printf("Ente
#includeintmain(){intn,sum=0;printf("请输入一个整数:");scanf("%d",&n);while(n){sum=sum+n%10;n/=10;}printf("
#include#includeintmax(inta,intb,intc){c=c>(a=a>b?a:b)?c:a;returnc;}intmain(){inta,b,c;scanf("%d%d%d
#include#defineSURPLUS(a,b)(a%b)main(){inta,b;printf("pleaseinputinteger:");scanf("%d,%d",&a,&b);pri
#includevoidmain(){\x09intm,n,i,cnt=0;\x09inttemp[3];\x09printf("Inputm&n(m>100,m再问:谢谢大神