c语言中输入一个数,判断其是否为5的倍数.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/28 09:30:35
#include"stdio.h"#include"math.h"main(){inti,n,flag=1;printf("PleaseInputanumber:");scanf("%d",&n);f
#include <stdio.h>void main(){ int n; &
#includeintmain(void){intn,a;scanf("%d",&n);a=0;if(n%3==0)++a;if(n%5==0)++a;if(n%7==0)++a;if(a==0)pr
#includeintmain(){charinput;scanf("%c",&input);if(input>='a'&&input
main(){intn;printf("pleaseinputanumber\n");scanf("d%",&n);if(n%2==0)printf("thenumberisoushu");elsep
楼上的太复杂了!intmain(){inta=0,num=0;scanf("%d",&num);for(inti=2;i
#includeintmain(){inti;voidfun(inta);printf("输入数字:");scanf("%d",&i);fun(i);return0;}voidfun(inta){if
#includeintmain(){intnum,temp;intsum=0;printf("Pleaseinputanumber:");scanf("%d",&num);temp=num;while
一直除十直到为0再答:除一次,i++再问:i=1,然后每除10,i+1?再答:开始0再问:令I=0,然后除以10,直到原数为0,最后输出I?再答:对
方法很多啊,比如判断每一位是否是数字,再比如先把字符串atol转换成数字,再转换成字符串,看是否相等.再问:第一条再答:既然限制了用空格分开,一个回车输入10个数,只能先把变量或数组都赋值成0,用sc
1.整型:intnTest=0if(nTest==0)if(nTest!=0)2.浮点型:#defineEPISTION0.000001/*精度*/floatfTest=0.0if((fTest>=-
#includevoidmain(){inti,j,k,m;printf("inputdata:");scanf("%d",&m);/*输入一个3位数*/i=m/100;j=(m-100*i)/10;
水仙花数是指一个n位数(n≥3),它的每个位上的数字的n次幂之和等于它本身.(例如:1^3+5^3+3^3=153)注意我这只限于3位数#includevoidmain(){intx,y,z;intn
/>#include<stdio.h>#include<string.h>int main(){ char s[20]; scanf(&
#include"stdio.h"#include"iostream"intmain(){inti,x,y=1;scanf("%d",&x);for(i=2;i
intiIsRunAround(intnNum){intnCount=0;//位数intnStep=0;intnCur=nNum;intarrNumber[10];//各位数,个位到最高位intarr
//提示:153370371407是水仙花数#includevoidmain(){inti,j,k,n;printf("请输入一个三位整数\n");scanf("%d",&n);i=n/100;/*分
#includevoidmain(){\x09intyear;\x09printf("请输入年份:");\x09scanf("%d",&year);\x09if((year%4==0&&year/10
#include#includeintmain(){intn,i,k,prime=1;do{printf("Pleaseinputapositivenumber:\nn=");scan
#includemain(){inta,b;scanf("%d",&a);for(b=1;