c语言程序设计,输入一个4*4的矩阵,求四个边上元素的和
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/30 05:33:30
搞那么复杂干嘛,就是一位数组排序,让后放到二位数组里面,一位数组排序网上一大堆,搜下吧再问:亲,我就只要答案,不是方法。即能解决这个问题的程序代码。加油呀!再答:#incluevoidbubble_s
#include#includevoidmain(){inta,t,m,sum=0;couta;for(inti=0;i
#includeintmain(){intn;printf("请输入一个整数:");scanf("%d",&n);if(n>0){if(n%2)printf("正奇数\n");elseprintf("
#include<stdio.h> voidmain() { inti; printf("请输入1-7数字\n&q
#includeintmain(){inta=0,b=0,c=0,n;printf("请输入一个三位数:");scanf("%d",&n);a=n/100;b=n%100/10;c=n%10;prin
#includeintmain(void){inti;for(i=100;i
#includeintmain(){inta,b,i,t;intk=0,sum=0;scanf("%d",&a);//输入整数at=a;if(a/10==0){k=1;sum=a;printf("%d
voidfun(intm,intn){for(inti=m;i
voidchange(inta,intb){inttemp;temp=b;b=a;a=temp;printf("\n交换后的两个整数为:%d%d\n",a,b);}
#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol
已发送,#include//头文件#include#includevoidmenu();//声明部分voidadd();//"+"voidsub();//"-"voidmul();//"*"voidd
#include#include"math.h"intmain(void){\x09printf("请输入三角形的三条边:\n");\x09floata,b,c,s,sum=0;\x09scanf("
count=0;for(fen1=1;fen1
#includeintmain(){doublef;scanf("%lf",&f);printf("%.3lf",f);//这样输出已经默认4舍5入return0;}
入门级程序#include#definepi3.14voidmain(){doubler;scanf("%lf",&r);printf("周长:%.2lf\n",2*pi*r);printf("面积:
帮你写了一个如下:#include <stdio.h>#include <stdlib.h>int main(){ int a
main(){intn,i=1,sum=1;scanf("%d\n",&n);if(n%2!=0){for(;i
#includeintmain(){inta,b=0;inti,u[3]={0};scanf("%d",&a);for(i=0;i再问:一个20位以上的数呢例如21位数变成7位数,三个一组相加所得的数
#include#includeusingnamespacestd;voidmain(){chars[4];intn,k;cin>>s;sort(s,s+4);n=(s[0]-'0')*10
#include#includeintmain(){inta[5],i,j=0,max=0;for(i=0;i