C语言编写一个函数计算n!
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#includelongfactorial(intm,intn){longsum=1,sum1=1;inti;if(m-n>n){for(i=m;i>m-n;i--)sum*=i;for
#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s
intfun(intn){//在该函数体中求1~n的累加值//用return语句返回累加值intsum=0;inti;for(i=1;i
南开二级C语言100题1.m个人的成绩存放在score数组中,请编写函数fun,它的功能是:将低于平均分的人作为函数值返回,将低于平均分的分数放在below所指定的函数中.2.请编写函数fun,它的功
intjc(intx){returnx==1?1:jc(x-1)*x;}再问:可以编一个完整的么?我直接运行试一下。。。新手,不好意思,,,,谢谢再答:intjc(intx){returnx==1?1
/*850-597Pressanykeytocontinue*/#include <stdio.h>void Show(int a[],int n)
#includemain(){doublex,y;scanf("%lf",&x);if(x
#includeintmain(void){intn;inti,j;floatsum=1.0;floatdex=1.0;printf("输入一个数:");scanf("%d",&n);for(i=2;
main(){intsum,i,j,n;ints[n][n];for(i=0;i
#includemain(){\x05intm,n;\x05ints=1;\x05intpower(inta,intb);\x05printf("inputmn(m^n):\n");\x05scanf
#include <stdio.h>float area(float r){ return 3.14159 *&nb
#includemain(){inti,j,n,k,t;doublesum=2;printf("inputanumber:\n");scanf("%d",&n);j=2;k=1;for(i=1;i再问
#include <stdio.h>int main(){ float x, tax = 0;
#includevoidfun(intn){inti;for(i=2;i
#include#defineN9voidmain(){inti,j,a[N][N]={0};for(i=1;i
main(){inta,b,c;//a是输入测试值,b是分段值,c是条件标志printf("inputthevalueandpercentils:\n");scanf("%d%d",&a,&b);//
#include"stdio.h"intsum(intn);main(){inti,n,s=0;printf("Inputn:");scanf("%d",&n);printf("%d\n"
intsum(intn){ints=0;inti=1;boolflag=true;for(;i再问:boolflag=true;什么意思啊,不对的啊再答:C语言中的布尔型,不是bool吗?那你试试bo
#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i
以往写的#includeintfun(intn){if(n==1||n==2)return1;elsereturnfun(n-1)+fun(n-2);}intmain(void){intn,i=0;p