c语言输入十个数排序
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#includevoidmain(){floata,b,c,t;scanf("%f,%f,%f",&a,&b,&c);if(a>b){t=a;a=b;b=t;//实现a和b的互换}else;if(a>
#includemain(){FILE*fin,*fout;fin=fopen("maopao!.in","r");fout=fopen("maopao!.out","w");inti,j,t;int
定义四个变量intn,max,min,sum;先读一个数据scanf("%d",&n);sum=max=min=n;再循环9次,输入9个数,同时,累加,比较大小for(i=0;imax)max=n;i
求和应当是:#include#includemain(){inti,up=0,down=0,data[10];for(i=0,i0)up+=data[i];elsedown+=data[i];}pri
用数组main(){inti,m=0,n=0,a[10];printf("input10numbers:\n");for(i=0;i
voidmain(){inti=0,sum=0,max,num;floatavg=0.0;for(i=0;imax)max=num;}sum=sum+num;}avg=sum*1.0/20;print
#includevoidmain(){inta,b,c,d,e;printf("请分别输入四个数:\n");scanf("%d%d%d%d",&a,&b,&c,&d);printf("原顺序:%d%d
输入10个数,然后按照升序和降序输出?再问:是这样的,着10个数要从键盘输入例如:输入:1598122130-19输出:15998812212130-1-19再答:#includevoidmain()
额,这个问题是个很简单的问题,只有2个数字而已,只要一个比较就行了啊.#includevoidmain(){inta,b;scanf("%d%d",&a,&b)if(a
#includevoidmain(){inta[10];inti,n=0;floatsum=0;for(i=0;i
# include <stdio.h>#define N 10//元素个数void sort(int a[], int
/*C语言输入十个数,判断正数的个数以及它们的平均值*/#include"stdio.h"voidmain(){floatave=0;intval;inti;intn=0;floatsum=0;pri
因为值的交换在函数里面,交换是无效的,需要用地址的交换#includeintswap(int*a,int*b){inttmp;tmp=*a;*a=*b;*b=tmp;printf("a=%d,b=%d
#includevoidmain(){inta[10],i=0,j=0;intmax1=0,max2=0,tmp=0;printf("Pleaseinputnumbers:");for(i=0;i再问
#includemain(){floata[10],da,xiao,m=0;inti;printf("pleaseinput10data:");for(i=0;i
我后面补充!再问:哪呢?再答:#includevoidmain(){inti,j,k,f[10],max,min,a;for(i=0;i
intresult[3],tmp;result[0]=a;result[1]=b;result[2]=c;for(i=0;i
#includeintmain(){inta[10],temp;inti,j,k;for(i=0;i
1:#includeintmain(){inta[10],i,*p,j,temp;for(i=0;i