求x^2 y^2-8x 10y 16=0

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求x^2 y^2-8x 10y 16=0
已知x^2+y^2-6x-8y+25=0,求分式y/x - x/y的值

x^2+y^2-6x-8y+25=0x^2-6x+9+y^2-8y+16=0(x-3)^2+(y-4)^2=0∴x=3且y=4y/x-x/y=4/3-3/4=7/12

已知x^2+y^2-6x-8y+25=0 求y/x-x/y的值

x^2+y^2-6x-8y+25=0[x-3]^2+[y-4]^2=0x-3=0===>x=3y-4=0===>y=4y/x-x/y=4/3-3/4=7/12

2x+8y-xy=0(x>0,y>0),求x+y的最小值

xy移项,两边再同除以xy,得,2/y+8/x=1,再用x+y乘以上面的再问:你确认?这样解不出来啊再问:你确认?这样解不出来啊再答:得,2x/y+8y/x+2+8再用基本不等式得,答案16再问:0.

已知x+y-2+0,求(x^-y^)^-8(x^+y^)的值

如果你的上标是2次方的话可以这样做x+y-2=0可以推出x+y=2(X^-Y^)^-8(X^+Y^)=[(X+Y)(X-Y)]^-8(X^+Y^)=4(X-Y)^-8(X^+Y^)=4X^-8XY+4

3x=8y 求(2x+3y)/(x-2y)

x:y=8:3,设x=8t,y=3t,代入式子(2x+3y)/(x-2y)得,(2x+3y)/(x-2y)=(16t+9t)/(8t-6t)=12.5

已知实数x.y满足根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),求x,y

根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),根据二次根式有意义得:X+Y-8≥0,8-X-Y≥0,∴X+Y≥8,X+Y≤8,∴X+Y=8,左边为0,右边两个非负

已知x+y/x=11/8,求x-y/x+2y的值

(x+y)/x=11/88x+8y=11y8x=3yy=8x/3(x-y)/(x+2y)=(x-8x/3)/(x+16x/3)=(-5x/3)/(19x/3)=-5/19

已知:3x=8y.求(1)x+y/y (2)2x+3y/x-2y

3x=8yx/y=8/3(1)x+y/y=x/y+1=8/3+1=11/3(2)2x+3y/x-2y分子分母同时除以y得=(2x/y+3)/(x/y-2)=(16/3+3)/(8/3-2)=(25/3

若x,y为正数,且2*x+8*y-x*y=0,求x+y的最小值

2*x+8*y-x*y=02x+y8=xy>=2√2x*√8y=4√xy√xy>=4xy>=16x>=16/yx+y>=16/y+y>=2√16/y*√y=8所以最小值是8

x+y=8,x-y=6求x^2-y^2-2x-2y的值

x+y=8,x-y=6求x^2-y^2-2x-2y的值x^2-y^2-2x-2y=(x+y)(x-y)-2(x+y)=8*6-2*8=32

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知2x+2y=-8,4x+y=15求(x-y)^-(3x+2y)^

2x+2y=-8,.14x+y=15.21式*2-2式得3y=-21y=-7(x-y)^2-(3x+2y)^2=[(x-y)-(3x+2y)][(x-y)+(3x+2y)]=(-2x-3y)(4x+y

已知x,y满足x^2+y^2-6x+8y+25=0,求y^x的值

x^2+y^2-6x+8y+25=0x²-6x+9+y²+8y+16=0(x-3)²+(y+4)²=0x-3=0x=3y+4=0y=-4y^x=-4³

若x^2+y^2-8x-10y+41=0,求x/y+y/x的值

x^2+y^2-8x-10y+41=0x^2-8x+16+y^2-10y+25=0(x-4)^2+(y-5)^2=0所以x=4,y=5x/y+y/x=4/5+5/4=0.8+1.25=2.05

x^2+y^2-8x+10y+41=0求(x+y)^2013

x^2+y^2-8x+10y+41=0(x-4)^2+(y+5)^2=0x=4,y=-5x+y=-1(x+y)^2013=-1

x>0,y>0,x+y=1,求8/x+2/y的最小值?

这是很典型的一道均值不等式题,关键是乘以x+y因为x+y=1原式=(x+y)(8/x+2/y)=10+8y/x+2x/y>=10+8=18,所以最小值为18当x=2/3,y=1/3时取到最小值

已知x+y/y=11/8,求x-y/x+2y的值.

x+y/y=11/8说明11y=8(x+y)即8x=3y所以x-y/x+2y=3(x-y)/3(x+2y)=(3x-3y)/(3x+6y)=(3x-8x)/(3x+16x)=-5/19

已知x^2+4y^2-4x+8y+8=0,求x+y

(x²-4x+4)+(4y²+8y+4)=0(x-2)²+4(y+1)²=0则:x-2=0且y+1=0得:x=2、y=-1x+y=1