求各位数之和的c代码

#includeintf(intn);voidmain(){intn;scanf("%d",&n);f(n);}intf(intn){intge,shi,bai,qian,wan;ge=n%10;n/

#includeintmain(){inta,sum=0;scanf("%d",&a);while(a){sum+=a%10;a/=10;}printf("sum=%d\n",sum);return0

#includeintsum=0,count=0;voidarr(intk){count++;while((k/10)!=0){sum+=k%10;count++;k=k/10;}sum+=k;}vo

#include"stdio.h"main(){intdigit,k,m,s;for(k=1;k

#include#includeintabs(intx){returnx>0?x:-x;}intmain(){intn,a,b,t;scanf("%d",&t);while(t--){scanf("%

Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+iEndIfNext==>优化一点：Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+ii

代码：#include <stdio.h>int sum(int n){\x05int s = 0;\x05while(n>

按照你提供的函数intSearch(charname[5][100],intremain[5])的结构,恐怕检索不出来吧?增加了一个货物名形参,写成intSearch(charname[][100],

最后的那句判断应该是if(s%5==0)printf(...);你的判断条件错了

#includevoidmain(){inti,j,k;for(i=1;i

#includeintmain(){\x09inti;\x09intj;\x09intsum=0;\x09intmin;\x09introw;\x09intcolum;\x09inta[3][3];\

#includeintn,m=0;intmain(){scanf("%d",&n);while(n){m+=n%10;n/=10;}printf("%d\n",m);return0;}再问：看不懂。能

#include#include#includeusingnamespacestd;charused[30];charresult[30];intcount=0;voidquanpailie(char

#includeintmain(){inti,n;intsum=0;for(i=1000;i

#includeintmain(){intsum=0;intsumtemp=0;intge,shi,bai,qian;for(inti=1001;i

#includeintmain(){inti,sum=0;for(i=1000;i

#include"stdio.h"intmain(){\x09intnumber,i=0,sum=0;printf("pleaseinputanumber:");\x09scanf("%d",&num

我已经上机验证过了.clears=0fori=100to999a=int(i/100)b=int((i-a*100)/10)c=mod(i,10)ifa0andb0andc0andmod(a+b+c,

设多位数各个位的数都是9,那么a=1994×9=17946,b=1+7+9+4+6=27,c=2+7=9

令4444^4444＝X1.因为X=Sn*10^n+S(n-1)*10^(n-1)+S(n-2)*10^(n-2)+...S1^10+S0所以X-A=Sn*9^n+S(n-1)*9^(n-1)+S(n