求周长和面积的函数.然后再编写主程序,主程序要求

#include#definePI3.1415926doublearea(doubler){returnPI*r*r;}doubleperimeter(doubler){return2*PI*r;}i

CLEARSETTALKOFFINPUT"请输入半径:"TORL=2*PI()*RS=PI()*R*R"半径为R的圆的周长为:",L"半径为R的圆的面积为:",SSETTALKON

这个简单：#includeusingnamespacestd;intHe(intx,inty){intz;z=x+y;returnz;}intCha(intx,inty){intz;z=x-y;ret

#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s

PrivateFunctionSUM(Fir_LAsDouble,Fir_SAsDouble,Scend_LAsDouble,Scend_SAsDouble)AsDoubleSUM=Fir_L*Fir

#definePI3.14#includeusingnamespacestd;doublearea(floati){return(PI*i*i);}doublecircumference(floati

本人初学,答的不好的地方请见谅,程序代码如下：importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs

#include<stdio.h>double zc(double x, double y){    ret

#includeusingnamespacestd;floatmianji(floata,floatb){returna*b;}floatzhouchang(floata,floatb){return

if(s>=10)or(s

intHCF(intx,inty)//定义最大公约数函数{inti,change;if(x>y)//保证x是最小数{change=y;x=change;y=x;}for(i=x;i>=1;i--)if

有个题目就比较好说了.比如底边或长为x,高或宽为2-x,0

#include"stdio.h"#definePI3.141592653//定义πintmain(void){floatC,A,V,r;printf("请输入半径：");//提示输入scanf("%

p=1/4*(2*x*z+y*y-x*x-z*z);应该改为p=1.0/4*(2*x*z+y*y-x*x-z*z);或者p=1/4.0*(2*x*z+y*y-x*x-z*z);原因是：当进行运算时,1

chara;scanf("%c",&a);switch(a){case'y':圆形case'c':长方形cash'z':正方形}

Console.WriteLine("请输入圆的半径");intr=int.Parse(Console.ReadLine());doublecircle=2*3.14*r;doublearea=3.1

1.functions=mianji(r)s=pi*r*r;end2.functionl=zhouchang(r)l=2*pi*r;end

functionfun(d,h){if(d

#includevoidmain(){floatl,w;floatarea,girth;printf("pleaseinputlengthandwidthoftherectangle\n");scan

m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.