f(x,y)=sin根x4 y2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/10 23:11:23
函数f(x)=sin(3x+y)是偶函数,则f(-x)=sin(-3x+y)=f(x)=sin(3x+y)由正弦函数的性质sin(π-x)=sinx及周期性可得(-3x+y)+(3x+y)=π+2kπ
sin^2(x-y)+sin^2(y-z)+sin^2(z-x)=[1-cos2(x-y)+1-cos2(y-z)+1-cos2(z-x)]/2=3/2-[(cos2xcos2y+sin2xsin2y
y'=f'(sin²x)*(sin²x)'+f'(cos²x)*(cos²x)'=f'(sin²x)*(2sinxcos)+f'(cos²x
见图,复合函数求导.
dy/dx=2xf'(x²))cosf(x²)再问:没有过程吗?再答:复合函数求导法则
y'=f'(sinx^2)*cosx^2*2x-f'(cosx^2)*sinx^2*2x
dy/dx=y'=f'[2x/(x-1)]*[[2x/(x-1)]'=sin[2x/(x-1)]²*-2/(x-1)²=-2sin[2x/(x-1)]²/(x-1)
设函数f(x,y)=sin(x+y),那么f(0,xy)=(sinxy)应该是sin0+sinsy=0+sinxy=sinxy再问:limsinxy\2x=()补充x→0,y→3另外一道题
dy/dx=cos{f[sinf(x)]}*{f[sinf(x)]}'=cos{f[sinf(x)]}*f‘[sinf(x)]*[sinf(x)]’=cos{f[sinf(x)]}*f‘[sinf(x
这道题你先看sinx必然大于等于零吧,sin((1-y)x)也必然大于等于零的吧?整个函数都是大于等于0的吧?那么你只要找到可以让函数取到零的x和y就可以得到最小值0那么试着凑一下,y=1,x=pai
f(x)=sinxcosy+cosxsiny+cosxcosy+sinxsiny=sinx(cosy+siny)+cosx(siny+cosy)=(sinx+cosx)(siny+cosy)f(-x)
(根号2+根号6)÷4再问:如何做的??????????谢谢
x=-1,y=1xy=-1(2xy)2(x2-y2)-(-3xy)3+9x2y4-9x4y2=4(xy)2(x2-y2)-(-3xy)3-9(xy)2(x2-y2)=-5(xy)2(x2-y2)+27
由x²+y²-4x-10y+29=0得(x-2)²+(y-5)²=0所以x=2y=5所以x²y²+2x^3*y²+x^4*y&su
y'=f'(sin^2x)*(sin^2x)'=g(sin^2x)*2sinxcosx
f(x)=sin2(x+y/2)由于sin2x对称轴为π/4+kπ/2;故x+y/2=π/4+kπ/2x=π/4+kπ/2-y/2;将x=x=π/8代入,得y=π/4+kπ,根据y的范围可知:y=-3
若看不清楚,可点击放大.
y'=f'(sin(2x))*(sin(2x))'+(sin(f(2x)))'*f'(2x)=f'(sin(2x))*2*cos(2x)+cos(f(2
再问:谢谢了写的清楚明白
这是矩阵运算,表示对矩阵里的每个元素分别对应按公式计算.如果x、y不是矩阵就不需要加点了.