用c语言编写一元二次方程根
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希望有用,敬请采纳^_^#include#includeintmain(){voidroot2(doublea,doubleb,doubledisc);//定义方程有两个根时的函数voidroot1(
//只一处有错,还有一个注意输入格式.#include#includeintmain(){doublep,q,x1,x2,disc,a,b,c;scanf("%lf,%lf,%lf",&a,&b,&c
#include#includeintmain(){inta,b,c,x,p,x1,x2;printf("输入三个实数:\n");scanf("%d%d%d",&a,&b,&c);p=b*b-4*a*
scanf("a=%f,b=%f,c=%f",&a,&b,c&);c的输入啊,scanf("a=%f,b=%f,c=%f",&a,&b,&c);
double改做float再问:yiyuanercifangcheng.cpp(25):warningC4244:'=':conversionfrom'int'to'float',possiblelo
对于ax^2+bx+c=0intpanduan(inta,intb,intc){intm;m=b*b-4*a*c;return(m);}voidmain(){inta,b,c,flag,x1,x2,t
#includefloatf(float);voidmain(){floata,b,c,d,x1,x2,p,q;printf("a=");scanf("%f",&a);printf("b=");sca
#include"stdio.h"#include"math.h"doublex1,x2,p;floatfile1(floata,floatb){x1=(-b+sqrt(p))/2*a;x2=(-b-
您好!很高兴为您解答.如果刨除输入格式的问题,输入的那一行“scanf("%1f,%1f,%1f",&a,&b,&c);”应该改为“scanf("
#include#includevoidm(floata,floatb,floatc){\x09doublex1,x2;\x09x1=(-b+sqrt(b*b-4*a*c))/(2*a);\x09x2
/*结束程序请按“Ctrl+z”*/#include#includeintmain(){floata,b,c;doubled,x1,x2;printf("Enterthecoefficient
#include#includevoidmain(){floata,b,c,disc,x1,x2,realpart,imagpart;scanf("%f,%f,%f",&a,&b,&c);/*以a,b
#include#includeintmain(){doublea,b,c,disc,x1,x2,p,q,x;scanf("%lf%lf%lf",&a,&b,&c);disc=b*b-4*a*c;if
我也刚学C,费了好几个小时,终于把这个问题搞定了!已经运行过了,结果跟谭版结果一样,敬请放心使用.#include"stdio.h"#include"math.h"voidmain(){doublea
a=到数值(编辑框1.内容)b=到数值(编辑框2.内容)c=到数值(编辑框3.内容)你这里少了“.内容”再问:太给力了,你的回答完美解决了我的问题!
#include#include
double类型的不能直接用==0来判断,用fabs(a)
#include#includevoidmain(){floata,b,c,disc,x1,x2,realpart,imagpart;scanf("%f,%f,%f",&a,&b,&c);disc=b
1#include#includevoidmain(){printf("输入二次项系数、一次项系数和常数项:");scanf("%f%f%f",a,b,c);floatd=b*b-4*a*c;
#include"stdio.h"#include"math.h"#include"windows.h"voidmain(){floata,b,c;printf("----计算一元二次方程ax^2+b