用java输出12*3*4567

publicclassCat{publicstaticvoidmain(String[]args){intnum=2;drawDiamond(num);}privatestaticvoiddrawDi

publicclassTest{publicstaticvoidmain(String[]args){System.out.println("100-200间不能被3整除的数有:");intj=0;/

上面的程序错了publicclassT{publicstaticvoidmain(String[]args){intn=4;//可以修改intn2=n*n;int[][]arr=newint[n][n

importjava.io.*;publicclassTest{publicstaticvoidmain(String[]args)throwsException{BufferedReaderbr=n

如下所示Strings1=args[0];Strings2=args[1];Strings3=args[2];inta1=Integer.parseInt(s1);inta2=Integer.pars

public class Test{   public static void main(String[] a

//偶数的.呵呵int[]ary=newint[50];inti=1;intj=0;while(i再问：用java程序求出10000以内的能被5整除的数并放在数组中。谢谢！再答：//用java程序求出

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

publicstaticvoidmain(String[]args){ListarrayList=newArrayList();for(inti=1;i

publicstaticvoidmain(String[]args){for(inti=0;i

inth=5;//行数intx=65;//开始字符for(inti=1;i

这句话的意思就是参数J按照+2的数量递增,这个J比循环中的上一个参数要多2,比下一个要少2,如果i=1,那J就要大于等于1,并且小于等于3,以此来限制J,符合要求再问：谢谢,刚刚由于情急,忘记客气点了

汗.比二楼慢了一步.不过还是有点差异的.publicclassTest{publicstaticvoidmain(String[]args){int[][]a=newint[][]{{0,1,2,3,

importjava.io.BufferedReader;importjava.io.IOException;importjava.io.InputStreamReader;publicclassBa

for(intx=1;x

publicstaticvoidmain(String[]args){String[]a={"1","2","3","4","5","6","7","8","9","10","j","q","k"};

给你写了个程序可以实现,比如在主函数输入5,则输出表示5!(120)的数组[0,2,1],其中0表示个位数,2表示十位数,1表示百位数,程序如下：public static voi

packagelogicjava;importjava.util.Scanner;publicclassNumberJudge{publicstaticvoidmain(String[]args){

int[]arr={1,3,6,10,15,2,5,9,14,4,8,13,7,12,11};inti=0;//使用while遍历while(iif(i!=arr.length-1){System.o

publicclassTestArrays{publicstaticvoidmain(String[]args){int[][]a=newint[3][3];int[][]b=newint[3][3]