用递归编写程序:输出前20项斐波那契亚数列
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static void Main(string[] args) { 
C源程序:#include"stdio.h"voidmain(){intn=6;inti,j;for(i=0;i
#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i
添加一个文本框输入前N项的N值,再添加一个命令按钮即可PrivateFunctionF(NAsLong)AsLongIfN>2ThenF=F(N-1)+F(N-2)ElseF=1EndIfEndFun
PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli
#includeintmain(){inti,k,j,l,sum=0;i=1;k=0;for(j=0;j
publicclassFibonacci{publicstaticvoidmain(Stringargs[]){inti=1,j=1;for(intn=1;n
PrivateSubCommand1_Click()Fori=1To100Forj=1ToiFork=1TojIfi^2=j^2+k^2ThenPrinti;j;kNextkNextjNextiEnd
#includeusingnamespacestd;#include/*编写程序,计算并输出下面数列前20项的和,结果取3位小数.(C++)2/1,3/2,4/3,5/4,6/5,7/6,8/7,……
#include "stdio.h"#define ROW 14#define COL 12int main(){ch
#include <stdio.h>char* dg(char* instr, char* outstr, char* 
//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inti,j;for(i=0;i
#include"stdio.h"voidmain(){doublea,n,s=0;for(n=1;n
#include#includefloatmyfunction(intn,intx){if(0==n){return1;}elseif(1==n){returnx;}else{return((2*n-
#include"stdafx.h"voidmain(){ints=0;for(intn=1;n
#include<iostream>using namespace std;int main(void){ int line,i,j;&n
intSmallerThan=5;for(inti=1;i
楼主要用什么语言写啊C还是C++再问:C语言再答:#includevoidmain(){inti,j;for(i=0;i
longn=0;for(inti=1;i
1.dimi,jasIntegerfori=1to20j=j+i*(i+1)*(i+2)nextimsgboxj