编写一个程序,计算5*5的矩阵的主对角线之和

privatesubform_click()dimnaslong,snaslongn=inputbox("请输入n")fori=0tonsn=sn+2*i+1nextmsgbox"1+3+5+...(

#include<stdio.h>void main(){ int i,j,c[2][3]; int a[2][3]={{12,23,34

//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV

PrivateSubCommand1_Click()Dima,xAsSinglea=Val(Text1.Text)Ifa再问：x=x+a*0.2+3000*0.2怎么都乘0.2呀？

个人程度还不够好啊,写了好长才写出来,.：#include#defineMAX500main(){\x09inti=0,j=0,a[MAX][MAX]={0},n,number=1,mod=1;\x0

#include#include#includevoidmain(){inta[5][5],b[5][5],c[5][5],i,j;srand(time(0));for(i=0;i

INPUT"a=",aINPUT"b=",bPRINT"|a|+|b|=";abs(a)+abs(b)#includeinta,b;scanf("%d",&a);scanf("%d",&b);prin

VB程序PrivateSubCommand1_Click()Dima,iAsIntegeri=1Whilei<50s=s+(i+1)/ii=i+1WendPrint"s=";sEndSu

#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fact(n-1);}intmain(){printf("5!+10!=%d\n"

#includevoidmain(){floata,b,result;charc;printf("pleaseinputastatement:");scanf("%f%c%f",&a,&c,&b);s

#include#includevoidmain(){intsum,i;sum=0;for(i=1;i

程序框图如下：程序如下：s=1i=3DOs=s*ii=i+2LOOPUNTILi＞99PRINTsEND

#include <stdio.h>int main(){  float x, tax = 0; 

publicclassTestArray{publicstaticvoidmain(String[]args){intm=0;for(inti=1;iintn=1;for(intj=1;jn=n*j;

你好!这个是不是有点太简单了?你假设一个函数：functionf=fun1(X2)R=[];f=R*X2end主函数：clc;clearalli=1;whilei>0X2=input('请输入X2：\

,j,minv,mini,minj,sum=0;inta[4][4];printf("请输入矩阵中的16个数：");for(i=0;i<4;i++)for(j=0;j<4;j++)scan

doublefunction(intn){doublevalue=0;for(inti=1;i

好长啊,自己编吧==!

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main(){inta[3][3]={{1,2,3},{4,5,6},{7,8,9}}inti,j;intsum=0,s=0;for(i=0;i