编写函数fun它的功能是求n以内不包括n
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floatfun(int*a,intn){inti,sum=0;for(i=0;i
employee*delcre(employee*head,employee*head1){employee*p,*s,*q;p=head;while(head->age>55&&head->sex=
PrivateSubfun()ifimod2=0thenforx=itoastep2s=s*xnextxelseforx=(i+1)toastep2thens=s*xnextxendif试试看行不行吧
#includedoublefun(doubleh){returnfloor(h*100+0.5)/100;}
#include#includedoublefun(intn){doubles=0.0;for(inti=0;i
填写的内容为:inta=1,s=0;while(a
#include#includeintprime(inti){intk;for(k=2;k
/*是p=m!/n!(m-n)!*/floatfun(intm,intn){floatp,t=1.0;inti;for(i=1;i
#include#defineN10floatfun(intnum[N[N]){inti,j,k=0,sum=0;floataverage;//下面求数组周边元素的平均值for(i=0;i再问:顶角的
上面的错了应该是intfun(){inti,sum=1;for(i=1;i
#include#includevoidswap(intc[],intlen){inti=0;inttmp;for(;i{tmp=c[i];c[i]=c[len];c[len]=tmp;}}intmu
1,JAVA编的,n可以任意赋值publicdoublefun(intn){doublesum=0;for(inti=1;i1;n--){inti=max(a,n);inttemp=a[i];a[i]
#include <stdio.h>#include <stdlib.h>#include <math.h>double f
请楼主参考采纳intfun(intt){inti;intcurrent=0;for(i=1;totalt)break;current+=i;}returncurrent;}
voidfun(intn){inti;floatresult=0.0;for(i=1;i
Functions(ByValaAsInteger,ByValbAsInteger)AsIntegerDimiAsIntegerFori=1To1000IfiModa=0AndiModb=0Thens
1.intf1=0,f2=1,f3;2.returnf3;继续写:f3=f1+f2;f2=f3;f1=f2;
#include#includedoublefun(intn)//计算1!+2!+3!+.+n!,并赋值给fun{inti;doubles=0,t=1;for(i=1;i
voidfun(){intn,i,sum=0;printf("n=");scanf("%d",&n);for(i=n;i>=0;i--){if(i%5==0&&i%9==0)sum+=i;}print
intfun(intn){inti,m=1;for(i=1;i