编写函数完成如下功能:将长整型数中数字为偶数的数依次取出,构成一个新数返回,例如
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#includeusingnamespacestd;doublecentigrade(doubleF){doubleC=(F-32)*5.0/9;returnC;}intmain(){doubl
y+=j*1.0/(i*i);
#includelongfun(longx){intn=10,m=0;while(x){intt=x%10;if(t%2==0){m+=t*n/10;n*=10;}x/=10;}returnm;}vo
PrivateFunctionFun(mAsInteger)AsSingle'EndFunction
/*90897:7980923098:8903233201:1023378653:3568736451:1546383409:90438Pressanykeytocontinue*/#include&
#includevoidmain(){intm,i;floatt=1;printf("请输入m的值:");scanf("%d",&m);for(i=2;i
doublefun(intm);intmain(){inta;scanf("%d",&a);printf("%lf\n",fun(a));}doublefun(intm){doublesum=0.0,
你用这个代码调试看看,我写了能达到你的目的,可以输入5门,如果想输入其他的门数就把里面的5全改为你想查的门数!#include"stdio.h"voidmain(){\x09inti,a[5];dou
亲,这是我改好的程序#includevoidfun(long*s,intn){inti,j=0;longt[100];for(i=0;i
functionyout=myfun1(x,D)%myfun1helph=5%|-h,x>D%y=f(x)=|h/(D.*x),|x|
有个缺陷,如果是thisisatest,则把a也大写了,不知道这样是不是符合你的要求.(按你的题目讲是正确的)如果不符合,则稍加个判断即可.#include#includeintmain(){char
#includevoidmain(){inti,c=1,n;floatsum=0;printf("Pleaseinputn:\n");scanf("%d",&n);for(i=1;i
#include"stdio.h"doublesum(intm){\x09inti;\x09doublet;\x09for(i=2,t=1.0;i
例如:f(x)=x+1symsxa=0;b=1;I=int('x+1',a,b)结果:I=3/2
#include<stdio.h>void fanxu(int c[], int j);void main(){\x09int
main(){inta,b;longc;clrscr();printf(“inputa,b:”);scanf(“%d%d”,&a,&b);c=0;c+=a%10*100;c+=a/10;c+=b/10
#include <stdio.h>#include <stdlib.h>#include <math.h>double f
longfun(longx){for(inti=0;i
# include <stdio.h>int fun(int *a){ int i,j=0,qw,bw,sw,gw,
intfun(intm){inty=1;for(inti=2;i