编写求k!的函数再调用该函数求

#includedoublefun(doublex,doubley){returnx*x*x+y*y*y;}voidmain(){doublea=fun(3.4,2.8);doubleb=fun(10

main(){ints;s=getfactorial(6)+getfactorial(10)+getfactorial(20)printf("s=%d",s);}intgetfactorial(int

#include"stdio.h"voidmax_min(inta[],intn,int*max,int*min){int*p;*max=*min=*a;for(p=a+1;pif(*p>*max)*

function[X_max,X_min]=yougotit(X)X_max=max(X(:));X_min=min(X(:));end我直接在这里写的.不过估计没错.这个.嗯.有点耍滑.但是就是这样

#includeintsum(intn){ints=0;while(n){s+=n%10;n/=10;}returns;}intmain(void){ints=0;for(int

用递归函数#include#includeintinv(intx);main(){intsum=0,i;for(i=1;i

eturn是函数返回值语句,作用是返回调用该函数地方.在函数体内应该只有一个{if(n==1)return(1);elsereturnfact(n-1)*n;//计算n-1

#include<stdio.h>int getmax(int a,int b){      re

PrivateFunctionSUM(Fir_LAsDouble,Fir_SAsDouble,Scend_LAsDouble,Scend_SAsDouble)AsDoubleSUM=Fir_L*Fir

intjc(intx){returnx==1?1:jc(x-1)*x;}再问：可以编一个完整的么？我直接运行试一下。。。新手，不好意思，，，，谢谢再答：intjc(intx){returnx==1?1

#includevoidcount(floatstu[],float*p_sum,float*p_aver,float*p_max,float*p_min){\x09inti;\x09*(p_max)

Bigger(inta,intb){returna>b?a:b;}Biggest(inta,intb,intc){returnBigger(a,b)>c:Bigger(a,b):c;}

sum(n){intsum,i;if(i=1;i

==||童鞋.你是要返回输入的n个数的最大值,还是一个数组的最大值啊.返回输入n个数最大值的函数：#includeintMax(intn);//最大值函数声明intmain(){intn;scanf(

#include#includeboolisPrime(intnum){if(num!=2&&num%2==0)//除2以外的偶数都不是素数{returnfalse;}for(inti=3;i

#include#includeusingnamespacestd;intjust(intnum){for(inti=2;i

#includelongfac(intn){longz;if(n==1)z=1;elsez=n*fac(n-1);returnz;}intmain(){inti,n;longsn=0;scanf("%

#include#includevoidb1(){floatl,s,k;inta,b,c,h;printf("\n");printf("\n");printf("输入a,b,c的值\n");print

#includeintmaxy(int&a,int&b){intn,i,j;for(i=1;i>x>>y;s=maxy(x,y);cout

prime函数有错!int prime(int N){    int i;    if(N