编程实现:先提示用户输入一个整数,判断它是不是既能被3整除又能被7整除的数,

CLEARSETTALKOFFINPUT"请输入半径:"TORL=2*PI()*RS=PI()*R*R"半径为R的圆的周长为:",L"半径为R的圆的面积为:",SSETTALKON

stringa=Conlose.ReadLine();inti=.length;stringnewStr="";while(i>0){i--;newStr+=a[i].toString();}Cons

#includevoidmain(){\x05charc;\x05scanf("%c",&c);\x05if(c>='a'&&c

#includevoidmain(){charx[100];inti;printf("请输入英语句子\n");gets(x);x[0]=x[0]-32;for(i=1;x[i]!='\0';i++){

核心代码Scanners=newScanner(System.in);doubleresult;while(s.hasNextInt()){inti=s.nextInt();if(i/2==1){re

intfun(intn){returnn%2;}intmain(){intn;printf("\n输入要判断的整数");scanf("%d",&n);if(fun(n)==0)printf("\n%d

算法一：#includemain(){intn1,n2,gcd=1,k=2;scanf("%d%d",&n1,&n2);while(k0;i--)if(n1%i==0&&n2%i==0)printf(

//输入范例假设n赋值为4/*1234(回车)2345(回车)3456(回车)5678(回车)注意输入时数字间要有空格间隔*/#includevoidmain(){inti,j;intsum=0;//

#include<iostream>using namespace std;int main(){    int&nb

#includevoidmain(){intn;printf("请输入一个正整数:");scanf("%d",&n);intsum=0;if(n%2==1){for(inti=1;i

#includeintmain(){inta[4];inti;printf("Pleaseinpuetthe4numbers:\n");for(i=0;i{printf("PleaseInpuetth

if(flag==0){\x05intiLast,iNext;\x05iLast=sqrt(nums);\x05iNext=iLast+1;\x05printf("itisnotaperfectsqu

2种方法第一种：写计算圆形,长方形,正方形的函数3个floatcalculate1（）；floatcalculate2（）；floatcalculate3（）；在你的主程序你做一个switchcase

#include#include//因为用到了sqrt()函数,sqrt()为开根号usingnamespacestd;intmain(){cout

#includeusingnamespacestd;typedefstruct{intyear;intmonth;intday;inthour;intminute;intsecond;}Time;in

//看好记事本写的Judge.javapublicclassJudge{publicstaticvoidmain(String[]args){try{if(args.length!=3){Sy

#includeintmain(){intx,y;charch='0';intcount=10;scanf("%d%d",&x,&y);while(count--){while(ch!='A'&&ch

packageEx2_1;importjava.util.Scanner;classRectangle{publicstaticvoidmain(Stringargs[]){doublelength,

importjava.util.Scanner;classtest7{publicstaticvoidmain(Stringargs[]){Scannerscan=newScanner(System.

1、楼主注意=与==的区别：if(a%3=0)应该是手误吧?2、函数实现的时候不要带分号哦intx1(inta).建议楼主这样写int x1(int a){