大师作文网m2(p-q)-p+q
来源：学生作业帮助网 编辑：作业帮 时间：2024/09/23 09:32:59
=2(p+q)(3p-2q)再问：步骤？再答：就一步，是提取公因式2(p+q)
(2p+q)(8p-3q)-2p(2p+q)=(2p+q)(8p-3q-2p)=(2p+q)(6p-3q)=3(2p+q)(2p-q)
(p+2q)^2-2(p+2q)(p+3q)+(p+3q)^2=（p+2q-p-3q）²=(-q)²=q²
pV(p->q)pV(非pVq)1P->(Q->P)非pV(q->p)非pV(非qVp)1非p->(p->q)p->(q->p)
V:或^：且┐：非
[(p-q)³-2(q-p)²-2/3(q-p)]/[(p-q)/3]=3(p-q)²-6(p-q)+2(p-q)
=(2p²-pq+4pq-2q²)-(p²-q²)=p²+3pq-q²
q表示q!=NULL如果不空继续循环
那么8△m=4*8-(8+m)/2=10所以m=36
解原式=(p²-4pq+4q²)-2(p²+5pq+6q²)+(p²+6pq+9q²)=(p²-2p²+p²)
previousquestion先决问题
m²(p-q)-p+q=m²(p-q)-(p-q)=(m²-1)(p-q)=(m+1)(m-1)(p-q)
(1)原式=2(p+q)(3p+3q-1)(2)原式=(x-y)(2x-2y-x)=(x-y)(x-2y)(3)原式=(a-b)(m+n)(4)原式=12.1×(1.3+0.9-1.2)=12.1(5
6p+（p+q)-4q(p+q)=6p+p+q-4qp-4q^2=7p+q-4pq-4q^2
6p(p+q)-4q(p+q)＝(6P－4q)(p+q)m(a-3)+2(3-a)＝(m－2)(a-3)
6p(p+q)-4q(p+q)=（p+q)(6p-4q)=2(p+q)(3p-2q)
再答：我的回答满意吗？望采纳
6p(p+q)²-4q(p+q)²=2(p+q)²(3p-2q)
6p{(p+q)(p+q)}-4q(p+q)=2(p+q)[3p(p+q)-2q]=2(p+q)(3p²++3pq-2q)