若5x-3y=0,且xy不等于0
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你的问题可能有错误,如果“求代数式x²-2xy-5y²除x²+2xy=5y²的值”中的“=”为“-”的话解题过程如下:∵x²-xy-2y²=
3x2-2xy-8y2=(3x+4y)(x-2y)=0so3x+4y=0orx-2y=0x/y=-4/3or2
x-3y=0且xy≠0,所以x=3y(x≠0,y≠0)带入分式,(9y-3y+y)/(9y+3y+y)=7/13
x-3y=0x=3yx*2-xy+y*2/x*2+xy+y*2=(9y^2-3y^2+y^2)/(9y^2+3y^2+y^2)=7y^2/13y^2=7/13
3x²-2xy-8y²=0两边同除y²得:3(x/y)²-2(x/y)-8=0(3x/y+4)(x/y-2)=0x/y=2或x/y=-4/3
x+y=03x+y分之7x+3y=?=2x+x+y分之4x+3x+3y=2x分之4x=2
设(y+z)/x=(z+x)/y=(y+x)/z=k则y+z=kx,z+x=ky,y+x=kz三式相加2(x+y+z)=k(x+y+z)故当x+y+z=0时,k=-1,但xy-z不等于0,可知x+y+
因为xy不为0,所以3x^2-2xy-8y^2=0可以两边同时除以y^2,得3(x/y)^2-2(x/y)-8=0即(3x/y+4)(x/y-2)=0解得x/y=2或者x/y=-4/3希望有用.
2x^2+5xy-3y^2=0(2x-y)(x+3y)=0y=2x或者x=-3y当y=2x时(x^2-y^2)/xy=x/y-y/x=1/2-2=-3/2当x=-3y时(x^2-y^2)/xy=x/y
3x²-2xy-8y²=0(x-2y)(3x+4y)=0x=2y或3x=-4yx/y=2或x/y=-4/3
3x²+3xy=03x²=-3xy因为x不等于0所以x=-y所以x:y=1:-1
3x²-2xy-8y²=0(3x+4y)(x-2y)=03x=-4y,x=2y所以x/y=-4/3或2
2分之1或负4分之3
-2x+6xy-2y/(7x+5y)-9xy-(3x+y)=[3(x+y)-x-y]/[7x+5y-9/2(x+y)-3x-y]=2(x+y)/[-1/2(x+y)]=-4
2x2+5xy-3y2=0(2X-Y)(X+3Y)=0==>X=Y或者X=-3YXY不等于0,即X,Y都不等于0所以X:Y=X/Y=1或者-1/3
因为,x-y=3xy所以:-3x+6xy+3y/[(7x-5y)-9xy-(3x-y)]=[-3(x-y)+6xy]/[(7x-5y)-9xy-(3x-y)]=[-3*3xy+6xy]/[7x-5y-
x^2+xy-6y^2=0化简得(x-2y)(x+3y)=0x=2y或x=-3y分别带入2x^2-3xy+y^2/5x^2-7xy+2y^2化简即可.