若圆x方 y方-4x-4y-10=0上至少有三个不同点到直线ax by=0
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(x²+y²-3)(2x²+2y²-4)=242(x²+y²-3)(x²+y²-2)=24(x²+y²
因为3x方+xy-2y方=0,即(x+y)(3x-2y)=0,而x+y≠0,所以3x-2y=0原式=[(x+y)^2-4xy]/[(x+3y)(x-y)/(x+3y)(x-3y)=(x-3y)/(x+
4(x-y)^2-25(x+y)^2=[2(x-y)+5(x+y)][2(x-y)-5(x+y)]=-(7x+3y)(3x+7y)
很高兴喂你解答!原式=4√[(x^2+xy+y^2)/(x-y)*1/2√[(x^2-xy+y^2)/(x+y)*3√(x^3+y^3)=6√[(x^2+xy+y^2)/(x-y)*√[(x^2-xy
(x+y)方+4(x-y)方-4(x方-y方)=[(x+y)²-(2x-2y)²]²=[(x+y+2x-2y)(x+y-2x+2y)]²=(3x-y)²
∵3x+4y-10=0∴y=(10-3x)/4∴x²+y²=x²+(100-60x+9x²)/16=(25x²-60x+100)/16=[25(x-6
请采纳,谢谢!
像这种题目也可以用特殊值去做,比如令x=1,代入方程求出y,再代入所求的式子就可以得出答案.
直接将二式相乘,得(x²+ax+b)(3x+1)=3x³+x²+3ax²+ax+3bx+b=3x³+(1+3a)x²+(a+3b)x+b由于
=xy(4x²+4xy+y²)=xy(2x+y)²
(9x方-4y方)(9x方-4y方)=81x的4次方+16y的4次方-72x方y方
8x^2-6y^2=146x^2+4y^2=3814x^2-2y^2=52
x^4-13x^2y^2+36y^4=(x^2-4y^2)(x^2-9y^2)=(x+2y)(x-2y)(x+3y)(x-3y)
(x方+y方)(x方+y方-4)+4=(x方+y方)²-4(x方+y方)+4=(x²+y²-2)²在右上角点击【评价】,然后就可以选择【满意,问题已经完美解决】
(X-1/2Y)方
(x^2+xy+y^2)^2-4xy(x^2+y^2)=(x^2+y^2)^2+2xy(x^2+y^2)+x^2y^2-4xy(x^2+y^2)=(x^2+y^2)^2-2xy(x^2+y^2)+x^
4x方-y方-4x+1=(2x-1)^2-y^2=(2x-y-1)(2x+y-1)
已知x方-4x+4+|y+x|=0,===>(X-2)^2+ly+xl=0====>x=2,y=-2,代入求解即可.(平方数>=0,绝对值>=0)再问:我问一下你的======是什么意思?你能帮我把过
∵x²+y²+6x-2y+10=0∴(x²+6x+9)+(y²-2y+1)=0即(x+3)²+(y-1)²=0由平方的非负性可得(x+3)&
4x方-4xy+y方-4x+2y-15=(2x-y)^2-2(2x-y)-15=(2x-y-5)*(2x-y+3)4x方y方-5x方y方-9y方题目弄错了吧,应该是这样的吧=4x^2y^2-5xy-9