解方程(x-1)6的平方*(1-x)的四次方=3x 5
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4x²-4x+1=x²+6x+93x²-10x-8=0(x-4)﹙3x+2)=0x=4或-2/3
因式分解为(3x+2)(x-4)=0故x=-2/3x=4
再问:再答:字模糊再问:
4x^2-3x-1=0(4x+1)*(x-1)=0x=-1/4..x=1
6/(x+1)=(x+5)/x(x+1);(6x-x-5)/x(x+1)=0;(5x-5)/x(x+1)=0;∴x=1;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问
1)两边同时乘以x^2-9:(x-3)+6=0x=-3经检验,此为增根故原方程无解2)x^2-x=12x^2-x-12=0(x-4)(x+3)=0x=4,-3
使用换元法设X²+2X=Y则原方程化为Y-6/Y=1去分母Y²-Y-6=0(Y-3)(Y+2)=0Y1=3,Y2=-2将Y=3和Y=-2代入Y=X²+2X,X²
x²-3x+1=0x²+3x-1=0x1=(-3+√13)/2或x2=(-3-√13)/2
6x/(x+1)+2/(x^2+2x+1)=33x/(x+1)+1/(x+1)^2=33x(x+1)+1=3(x+1)^23x^2+3x+1=3x^2+6x+36x-3x=1-33x=-2x=-2/3
X的平方-2X-1=0x=[2±√(2^2-4*1*(-1)]/2=(2±2√2)/2=1±√2x=1+√2或x=1-√2
解方程:(1)(x²-5x)/(x+1)+24(x+1)/x(x-5)+14=0;(2).2(x²+1)/(x+1)+6(x+1)/(x²+1)=7;(3)(x̾
因为x-x=0,所以原式=0-2x/6=12x/6=-12x=-6x=-3
2x²-3x+1=0(2x-1)(x-1)=0x=1/2,x=1
根据解题过程,1+m≠0,m≠-1.(1+m)X²+3X=0X[(1+m)X+3]=0X=0或(1+m)X+3=0X1=0,X2=-3/(1+m).
2x的平方+1=3x2x的平方-3x+1=0(2x-1)(x-1)=0x1=1/2,x2=1
x^2-4x-1=0(x^2-4x+4)-5=0(x-2)^2=5x=5开根号+2或-5开根号+2
937***@qq.com:5(x-3)(x+5)=x²+(2x-1)²5(x²+2x-15)=x²+(4x²-4x+1)5x²+10x-7
3x²=4x-13x²-4x+1=0(3x-1)(x-1)=0x=1/3或x=1
x^2-x+√2-1=0△=1-4(√2-1)=5-4√2
X²-3X-1=0X²-3X=1X²-3X+9/4=1+9/4(x-3/2)²=13/4x-3/2=正负根号13/2x1=(3+根号13)/2或x2=(3-根号