计算26-x÷100×0.6
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等于1/X*(X-Y)
(1-x)/(x²+x-2)÷[(x²-1)/(x+2)]=-(x-1)/[(x-1)(x+2)]÷[(x-1)(x+1)/(x+2)]=-1/(x+2)×(x+2)/[(x-1)
(x^2-1/9)÷(3x+1)=(x-1/3)(x+1/3)÷(3x+1)=(x-1/3)÷3=x/3-1/9
原式=x2+2x+4(x+2)2÷(x−2)(x2+2x+4)3(x+2)÷1(x+2)(x−2)=x2+2x+4(x+2)2•3(x+2)(x−2)(x2+2x+4)•(x+2)(x-2)=3.
x÷6/35=26/45×13/25x=26/45×13/25×6/35x=676/13125
x2x−5+255−x=x2x−5-25x−5=x2−25x−5=(x+5)(x−5)x−5=x+5,故答案为:x+5.
-[-4X^2+3X+X^2-2X]÷X-[-3x^2+x]]÷X-3x-1
(x²-6x+9)÷x+3分之x²-9x+18,=(x²-6x+9)×(x+3)/(x²-9x+18)=(x-3)²(x+3)/[(x-3)(x-6)
(x²-y²)÷(x+y)=(x-y)(x+y)÷(x+y)=x-y
原式=[x(x−2)x(x−2)+2(x−2)x(x−2)-x(x+1)x(x−2)]•x(x−2)x+4=−(x+4)x(x−2)•x(x−2)x+4=-1.
解(4x²-1)/(2-4x)÷(4x²+4x+1)/x=(2x-1)(2x+1)/2(1-2x)×[x/(2x+1)²=-(2x+1)/2×[x/(2x+1)²
原式=x(x²-2x+3-3)×2/x²=x²(x-2)×2/x²=2x-4
(3x-3/x²-1)÷(3x/x+1)-1/x-1=3(x-1)/[(x+1)(x-1)]÷[3x/(x+1)]-1/(x-1)=1/x-1/(x-1)=(x-1-x)/x(x-1)=-1
2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?=2x/(x-2)(x+1)×(x+1)/(1-x)-x(x+2)/(x+2)(x-2)=2x/(x-2)(1
1/X(X+1)+1/(X+1)(X+2)+.+1/(X+99)(X+100)=[1/x-1/(x+1)]+[1/(x+1)-1/(x+2)]+.+[1/(x+99)-1/(x+100)]=1/x-1
原式=x²(x-1)/x(x+1)÷(x+1)(x-1)=x(x-1)/(x+1)÷(x+1)(x-1)=x/(x+1)²
X等于零你看式子会发现X可以消那么这个一元一次方程的的解就是X=0
原式=(x−2x+2-xx+2)•x+2x−1=−2x+2•x+2x−1=−2x−1.
27/26=1+1/26所以15*(1+1/26)=15+25/26
2.4/0.12*6.6=132