计算m-[n-2m-(m-n)]等于多少
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/28 19:19:51
(2m-n)/(n-m)+m/(m-n)+n/(n-m)=(2m-n)/(n-m)-m/(n-m)+n/(n-m)=(2m-n-m+n)/(n-m)=m/(n-m)欢迎采纳!
m+2m/n-m+n/m-n-2m/n-m=(m+2m-2m)/(n-m)+n/(m-n)=m/(n-m)+n(m-n)=-m/(m-n)+n/(m-n)=-(m-n)/(m-n)=-1
原式=[3-(m-n)][3+(m-n)]-[2-(m-n)][2+(m-n)]=[3²-(m-n)²]-[2²-(m-n)²]=9-(m-n)²-4
您好:(m+4n)(m-n)-6(m+2n)(m-3n)=m²+3mn-4n²-6m²+6mn+36n²=-5m²+9mn+32n²不明白,
解2m(m²-n+1)=2m³-2mn+2m
[5(m+n)2(m-n)]3÷【3(m+n)2(n-m)]2=125(m+n)的6次方(m-n)³÷9(m+n)的4次方(m-n)²=125/9(m+n)²(m-n)如
(m+n)^3-(n+m)(m-n)^2=(m+n)[(m+n)^2-(m-n)^2]=(m+n)[(m+n+m-n)(m+n-m+n)]=(m+n)(2m+2n)=2(m+n)^2
(2m+n)(m-n)-(m+2n)(n-m)=(2m+n)(m-n)+(m+2n)(m-n)=(2m+n+m+2n)(m-n)=(3m+3n)(m-n)=3(m-n)(m+n)
2+n(m-1)/m-m(n-2)/n
5(m+n)(m-n)-2(m+n)^2-3(m-n)^2=5(m^2-n^2)-2(m^2+2mn+n^2)-3(m^2-2mn+n^2)=5m^2-5n^2-2m^2-4mn-2n^2-3m^2+
2(m-n平方)
(m-n)^3+(n-m)m^2=(m-n)^3-(m-n)m^2=(m-n)[(m-n)^2-m^2]=(m-n)(m-n+m)(m-n-m)=-n(m-n)(2m-n)=-n(2m^2-3mn+n
原式=[(m-n)(m+n)+2n²]/(m+n)=(m²-n²+2n²)/(m+n)=(m²+n²)/(m+n)
原式=[(m-n)(m+n)+2n²]/(m+n)=(m²-n²+2n²)/(m+n)=(m²+n²)/(m+n)
2m-n/n-m+m/m-n+n/n-m=(2m-n-m+n)/(n-m)=m/(n-m)
(m-n)^3+(n-m)m^2=(m-n)^3-(m-n)m^2=(m-n)[(m-n)^2-m^2]=(m-n)(m-n+m)(m-n-m)=-n(m-n)(2m-n)=-n(2m^2-3mn+n
原式=【(m-n)(n-m)】^2=[m(n-m)-n(n-m)]^2=[mn-m^2-n^2+mn]^2=(2mn-m^2-n^2)^2=(m-n)^4
原式=-(m^2+2mn+n^2)=-m^2-2mn-n^2
我也没有用简便方法,是直接算出来的,希望能采纳.如下:(3m-n)(-3m-n)-(m-2n)^2-(m-2n)(2m-n)=-9m^2+3mn-3mn+n^2-m^2+4mn-4n^2-2m^2+4