设计一个圆类circle具有属性,圆心坐标x.y

#include"stdio.h"constdoubleP=3.14;classCircle{public:virtualdoubleArea();voidR(doubles);doublegetr(

好难!

classcircle{intx;inty;floatradius;public:voidsetpoint(int&x,;int&y);voidsetradius(float&radius);floa

namespaceEX1_4{publicclassshape{publicdoublePI=3.14;}publicclassRectangle:shape{publicintx,y,s,l;pub

classcircle{public:circle(doubleradius):_radius(radius){}~circle(void);private:double_radius;public:

classpoint;classshape{public:virtualdoublecircumference()=0;virtualdoublearea()=0;};#definePI3.14159

#include#include#include#include#definePI3.14159usingnamespacestd;classShape{public:virtualfloatgetA

以发送,楼主查收

classCircle{protecteddoubleradius;publicCircle(){radius=0;}publicCircle(doubleradius){thi

classcircle{floatradius;floatarea;public:circle(floatr){radius=r;}floatgetarea(void){area=3.14*radiu

把这三个类分别放到三个.java文件中,然后编译运行即可.publicclassCircle{privatedoubler;publicCircle(doubler){this.r=r;}public

随便回复点什么就OK,哈哈!

classcircle{public:circle(){radius=0;}circle(doubleradiuv){radius=radiuv;}voidgetparimeter(){parimet

2种差不多的方法,自己在VC6.0上面试试#include<iostream>usingnamespacestd;#definepi3.14classcircle{public:circl

#includeusingnamespacestd;classCircle{public:Circle(doubler=0):radius(r){}doubleArea(){return3.14*ra

用VB程序设计做的随机画十个圆的编程代码（抱歉：就知道这些）Dimr(10)AsInteger,iAsInteger'半径Dimx(10)AsInteger,nAsInteger'半径坐标Dimy(1

classCircle{privatedoubleradius;publicCircle(){this.radius=0;}publicCircle(doubler){this.radius=r;}p

#include#definePI3.14159usingnamespacestd;classcircle{private:doubleRadius;public:voidjiandan();};vo

#include <iostream>using namespace std;const double PI = 3.

根据题意实现代码如下：#include <iostream>#include <cmath>#include <string>usin