请编写函数fun:在形参指针所指的4个整数中找出最大值和最小值,最大的放在A中

employee*delcre(employee*head,employee*head1){employee*p,*s,*q;p=head;while(head->age>55&&head->sex=

printf("f=%f\n\n",f);out=fopen("outfile.dat","w");

#include"stdio.h"voidmax_min(inta[],intn,int*max,int*min){int*p;*max=*min=*a;for(p=a+1;pif(*p>*max)*

swap函数就是方法#include#include#includevoidswap(inta[][5],intn){inti,j,t;for(i=0;i

代码如下：#includeintmain(){char*months[12]={"January","February","March","April","May","June","July","Au

doublefun(doublex)｛{doublei,t=1.0,m=1.0,s=1;for(i=1;fabs(m/t)>=0.000001;i++){s=s+m/t;m*=(0.5+1-i)*x;

不知道你说是不是,例：10,20合成1020?如果是的话见下面代码,随手写的没测试,应该可以#include#includelongfun(inta,intb){chars[12];sprintf(s

int是整型long是长整型long的空间比int大int只能定义数-32767到32767大于这个范围用long定义按标准规定int的长度是16位或者32位,long是32位.大部分C++编译器中i

voidfun(intp,intn,inta[]){inti,t=0,j,x=0;for(i=p+1;t

#include#includeintprime(inti){intk;for(k=2;k

#include#includedoublefun(intn){intm=3,i;doubles=0;while(m

voidfun(int*s){intmax,min,i,j;maxs[0];min=s[0];i=0;j=0;while(*s!='\0'){if(maxs[j])min=s[j];i++;}a=ma

#include#defineN10floatfun(intnum[N[N]){inti,j,k=0,sum=0;floataverage;//下面求数组周边元素的平均值for(i=0;i再问：顶角的

#include <stdio.h>#include <stdlib.h>#include <math.h>double f

#includeinta[50];intfun(intm){intn=0;for(inti=1;i

int*addMetrix(int*a,int*b,intn){inti,len=n*n,res*;res=(int*)calloc(len,sizeof(int));for(i=0;ires[i]=

#includefloatfun(intn){inti;floatx,y;floatsum=0.0;for(i=0;i

不知道是不是你想要的#includedoublefun(intm){inti=1;doublesign=-1;doubles=1;while(i++

functionfun(d,h){if(d

#includeintfun(char*pszText,intnLen){intnCount=0;charchTemp=0;for(inti=0;i='a'&&chTemp='A'&&chTemp