输入十个数,输出他们的平均值及大于平均值的那些数,C
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#include“stdio.h”#defineMAX100voidmain(){intmark[MAX],sum=0,mark=0,j=0,aver=0;printf("请输入学生成绩,输入负数结束
#includeintmain(void){intx[10];intsum=0;inti=0;intavg=0;for(i=0;i
错误在average里的:floatsum=b[0];sum变量本来是全局的,在average里改变值后,在main里也是当然也能看到改变.可是,在average里在定义一sum,此时,后面的sum=
voidmain(){inti=0,sum=0,max,num;floatavg=0.0;for(i=0;imax)max=num;}sum=sum+num;}avg=sum*1.0/20;print
已经运行确认了:#includemain(){intavg,i,sum=0,a[11];printf("请输入十个整数\n");for(i=1;i
#includevoidmain(void){intA[10],max,min,num=0,all=0;//数组,最大数,最小数,大于平均数的个数,所有数之和doubleave=0.0;//平均数pr
先贴结果:123456789106.0000007.0000008.0000009.00000010.000000再贴代码:#include#include"conio.h"main(){inti;f
#includevoidmain(){inta[10];inti,n=0;floatsum=0;for(i=0;i
# include <stdio.h>#define N 10//元素个数void sort(int a[], int
aver不能是整型,aver=sum/10会默认取整的.你的if是需要写在循环里的,你现在程序运行到运算aver那里时,i的值是10,后边的if没有进循环,i就没有重新赋值,a[10]数组越界了
/*C语言输入十个数,判断正数的个数以及它们的平均值*/#include"stdio.h"voidmain(){floatave=0;intval;inti;intn=0;floatsum=0;pri
FunctionAverage(mySinge()AsSingle)AsSingleDimsnAsSingleDimcnAsInteger,iAsIntegercn=UBound(mySinge)-L
#includemain(){floata[10],da,xiao,m=0;inti;printf("pleaseinput10data:");for(i=0;i
#include<stdio.h>int main(){ int a[10],i,num=0; float ave
#include#includeusingnamespacestd;constintN=1000;intmain(){inta[N],i,sum=0,ave;for(i=1;i>a[i];for(i=
用c语言吧:#includevoidmain(){inti;floata[10],avg,temp1=0,temp2=0,fc;for(i=0;i
#includevoidmain(){floata,b,c,d,sum,average;printf("请依次输入4个实数,以空格间隔,以回车键结束:\n");scanf("%f%f%f%f",&a,
#includeusingnamespacestd;voidmain(){inti,n;floata[50],sum=0.0,ave,min;coutn;for(i=0;i
PrivateSubCommand1_Click()a=InputBox("请输入数字","提示")b=InputBox("请输入数字","提示")Print"和:"&Val(a)+Val(b)Pri