随机100个数,统计被7整除的个数VB
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privatesubform_click()dimnasinteger,iasintegerfori=7to1000ifimod7=0thenn=n+1nextprintnendsu
3515再问:求过程,c语言的再答:你大一?再问:中职再答:是妹子?再问:不是再问:大哥帮帮忙再问:大哥帮帮忙再答:按说应该很简单的啊再答:你怎么学的?再问:刚学再答:看书啊再答:看书啊再问:而且现在
PrivateSubCommand1_Click()DimiAsIntegerDimnAsIntegern=0Fori=1To100IfiMod3=0Thenn=n+1Printn;iEndIfNex
21X5=10521X21=44121-5+1=17个
Dimi,tjAsIntegertj=0Fori=100To10000IfiMod7=0AndiMod3=0Thentj=tj+1NextMsgBox"个数为"&tj
PrivateSubCommand1_Click()Dima(50),i,nRandomizeFori=1To50a(i)=Int(Rnd*191)+10Printa(i);IfiMod10=0The
$num=array('9','21','12','55','100');foreach($sumas$s){if($s%3==0||$s%7==0){echo$s;}}
还要写吗?再问:不会啊,怎么写呢?再答:你等下,我帮你写一个再答:参考代码:#include#includeintmain(intargc,char*argv[]){\x09inti,j=0;\x09
很简单.#includevoidmain(void){inti;intcount=0;/*计数*/for(i=100;i
//C#代码privatevoidForm1_Load(objectsender,EventArgse){//取出符合条件的数Listnums=newList();for(inti=100;i
inta3=0,a7=0,a37=0;for(inti=1;i
voidmain(){inti;intmark=0;for(i=1;i
PrivateSubCommand1_Click()Fori=1To100IfiMod7=0Thenn=n+1EndIfNextiPrintnEndSu
#include"stdio.h"voidmain(){inta[10];inti=0;for(i=0;i{scanf("%d",&a[i]);}for(i=0;i{if(a[i
这个程序不难,不知你要统计什么呢?
intcount=0;for(i=1;i
#include#includemain(){inta[30];intnCount=0,i=0;for(i=1;i
#includeintmain(){intcount=0,i;for(i=0;i{if(i%7==0&&i%11!=0){count++;}}printf("%d\n",count);return0;
Java程序:importjava.util.Random;publicclassTest{\x05\x05\x05publicstaticvoidmain(String[]args){\x05\x0
能被4整除的有(2008-1000)/4+1=253个其中能被100整除的有(2000-1000)/100+1=11个所以能被4整除但不能被100整除的数有253-11=242个