sin^2(1°)等于-搜答案-大师作文网

令x=cosα,y=cosβ,z=cosγ,则1=(sinα)^2+(sinβ)^2+(sinγ)^2=(1-x^2)+(1-y^2)+(1-z^2)=3-(x^2+y^2+z^2),所以x^2+y^

2sin@+cos@等于?

(2sina+cosa)=-5(sina-3cosa)7sina=14cosasina=2cosa

原式=[1-(2sinacosa)^2]=(1+2sinacosa)(1-2sinacosa)=(sin^2a+cos^2a+2sinacosa)(sin^2a+cos^2a-2sinacosa)=(

因为sin2α=2sinαcosα当α=A/2时,代入上式,2sinA/2cosA/2=sinA再等效替代A=α(只是字符而已,不具意义)2sinα/2cosα/2=sinα

sin@2-cos@2等于

-cos2a再问：�о��再答：��

(1-cosα)/sinα为什么等于sinα/(1+cosα)为什么等于tan(α/2)(1-cosα)/sinα=(1-cosα)(1+cosα)/[sinα(1+cosα)]=(1-cos

因为sin²a+cos²a=1所以cos²a=1-sin²a所以左边=(sin²a+cos²a)(sin²a-cos²a

通分即可1/1+sinα+1/1-sinα=(1-sinα)/[(1+sinα)(1-sinα)]+(1+sinα)/[(1-sinα)(1+cosα)]=(1-sinα)/(1-sin²α

积化和差,sin(a+b)=sinacosb+cosasinb,1sin(a-b)=sinacosb-cosasinb,21-2,sin(a+b)-sin(a-b)=2sinacosb;令a=mx,b

sinα=2cosαcosa=sina/2又sin²a+cos²a=1sin²a+sin²a/4=1sin²a=4/5sin²a+1=9/5

sin^2是sinx的平方sin260等于sin80最后一个没太看明白……

sin(1+派)等于.

sin(1+π）=sin1

45度

1公式(cos^2)X+(sin^2)X=1

sinα+cosα=1/2两边平方sin²α+2sinαcosα+cos²α=1/4sin²α+cos²α=1所以sinαcosα=-3/8

这是因为:方法一:(cos^2)15°-(sin^2)15=(cos15+sin15)(cos15-sin15)=[sin(90-15)+sin15][sin(90-15)-sin15]=(sin75

sin²1°+sin²2°+sin²3°...+sin²45°+sin²46°...+sin²89°＝sin^2(90-89)+sin^2(

sin(π/2-x)=cosx原式=sin^21°+……+sin^244°+1/2+cos^244°+……+cos^21°=44+1/2=89/2

sin80°=cos10°sin^280°=cos^210°sin^210°+sin^280°=sin^210°+cos^210°=1

有点蒙,看完你的问题,大概是这样的吧1－2sin²22.5°吧等于1－2sin²22.5°=cos(2×22.5°)=cos(45°)