vb求100-1000之间共有多少个整数满足他的各位数字之和为5,并显示这些数
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/24 08:28:17
PrivateSubCommand1_Click()Dima(1To20)Dimmax,ave,min,summax=0min=300Print"产生的20个数为:";Fori=1To20a(i)=I
subcommand1_click()dimiasinteger,sasintegers=0fori=1to100if(imod3=0andimod7=0)thens=s+inextmsgboxsen
Dimn,x,r,sAsSinglen=2s=0DoWhilen再问:能说一下算法的思路吗?再答:首先1不是素数,就用枚举将2到1000的每个数列举出来,再逐个检验,即从2到n/2一一举例,判断是否能
PrivateSubForm_Load()DimstrAsStringFori=100To200IfiMod3=2AndiMod5=3AndiMod7=2Thenstr=str&""&iEndIfNe
dimnum3asintegerfori=1to1000ifimod3=0thennum3=num3+iendifnext
PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima
Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+iEndIfNext==>优化一点:Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+ii
PrivateSubCommand1_Click()s=0Fori=100To200IfiMod3=0Thens=s+iEndIfNextiText1.Text=sEndSu
1填写imod6=0,指的是余数要等于0;2填写S,表示要把S输出.
sub平方和()dimsumdimiaslongsum=0fori=1to100sum=sum+i*inextiendsu
2500再问:过程,谢谢再答:1+3+5+...+9999+97+95+...+1(1+99)×50÷2=2500
nd*(b-a+1)+a;这样就会有小数出现的
dimiasintegerdimsumasintegersum=0fori=100to200step5ifimod30thensum=sum+inext
PrivateSubCommand1_Click()Fori=100To999IfIsPrime(i)Thenn=n+1Printi;IfnMod10=0ThenPrintEndIfNextiEndS
PrivateSubCommand1_Click()Dimoushu%,danshu%,sum%oushu=0danshu=0Fori=1To10Randomizesum=Int(Rnd*100)If
Fori=100To999IfiMod10=3AndiMod7=0ThenPrintiEndIfNexti
PrivateFunctionfact(n&)AsBoolean'错误1:参数n的数据类型应该与command1_click事件里的i类型一致Dims&'错误2:s的类型也应该是长整型(&),你原来定
PrivateSubCommand1_Click()Fori=iTo100IfiMod5=0OriMod7=0Thens=s+iEndIfNextiPrint"能被5或都7整除的数之和为"&sEndS
楼上算法有问题,多了几个PrivateFunctionprime(nAsInteger)AsBoolean'返回值=True是素数,False不是素数DimkAsIntegerprime=TrueFo
Option ExplicitPrivate Sub Form_Load()RandomizeMe.AutoRedraw = TrueDim