x 1200-x=2 3 解

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(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么

将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(

45+6x=5x+906x-5x=90-45x=45(23%+6x)*5=(4x+23%)*6115%+30x=24x+138%30x-24x=138%-115%6x=23%x=23/600(3+6x

两边乘(20+x)(25-x)1000-65x+x²=460+43x+x²108x=540x=5

23x+19=39+3x23x-3x=39-1920x=20x=125-2x=5+2x25-5=2x+2x20=4xx=5完整不?

(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x

X/(x-30)=(x+40)/XX^2=(X-30)*(X+40)X^2=X^2+40X-30X-120010X=1200X=120

只有一个实根.设f(x)=x^3+2x-19为单调增函数.所以只有一个实根.下面来求这个实根由于f(2)=-7f(3)=11所以这个根在（2,3）内.利用二分法求这个解.取x0=5/2f(5/2)=1

15x=23x-248x=24x=312+5x=3x-82x=-20x=-103(x-3)=9-(x+6)4x=9+9-6=12x=34+x=4x-173x=21x=7

5x+35=140-2x5x+2x=140-357x=105x=159x-27=70+4x9x-4x=70+275x=97x=97/512+7x=2x+327x-2x=32-125x=20x=4250

x-60%x=2400.4x=240x=600x+20%x=241.2x=24x=201-25%x=十六分之三1-3/16=x/413/16=x/4x=13/4160%x-x=90.6x=9x=155

x^3-x^2-2x=0x(x^2-x-2)=0x(x-2)(x+1)=0x=0或x=-1或x=2

本人提供一个解法：由于(x-2004)/(x-2005)=1+1/(x-2005),其它三个分式同样进行拆分,最终得出：[1+1/(x-2005)]-[1+1/(x-2006)]=[1+1/(x-20

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=

(x+12)*(x+12)=x*x+360x*x+144+24x=x*x+36024x=360-144=216x=216/24=9楼下的你复制我的做什么

(x+x)+(x-x)+(xx)+(x/x)=1002x+0+x²+1=100x²+2x+1=100（x+1）²=10²x+1=10或x+1=-10x=9或x=

(23-17)m=306m=30m=516x+4x+2x=264(16+4+2)x=26422x=264x=1232x-7x-5x=420(32-7-5)x=42020x=420x=21

问题是不是X2=(X+30)*(X-18）啊?要是上面的话就这样X2=X*X-X*18+30*X-30*18=X2+12X-540移项得：X2-X2-12X=-540,即-12X=-540,X=45*