x*n-y*n的分解是什么定理-搜答案-大师作文网

f(x)=x^nf'(x)=lim(y->0)[(f(x+y)-f(x))/y]=lim(y->0)[(x+y)^n-x^n]/y=lim(y->0)[nC1x^(n-1)+nC2x^(n-2)y+.

m²(x-y)+n²(y-x)=m²(x-y)-n²(x-y)=(m²-n²)(x-y)=(m+n)(m-n)(x-y)

|m+4|+n^2-2n+1=0,绝对值与平方都不小于零,所以m+4=0,(n-1)^2=0,即m=-4,n=1,所以x^2+4y^2-(mxy+n)=n^2+4y^2-(1-4xy)=(x+2y)^

(m+n)(x-y)-(m+n)(x+y)=(m+n)[(x-y)-(x+y)]+(m+n)(-2y)=-2y(m+n)(因式分解答案）=-2my--2ny(计算题答案）

（1）3x的n次方y+9x的n-1次方y的平方+四分之一x的n+1次方=x的n-1次方(9+3x+x²/4)=x的n-1次方(3+x/2)²（2）（4x的平方+3x）的平方-(x+

上式等于-2X^(n+1)Y^n乘以(X^4n-2X^2nY^2+Y^4)等于-2X^(n+1)Y^n(X^2n-Y^2)^2等于-2X^(n+1)Y^n(X^n+Y)^2(X^n-Y)^2

12m(x+y)的3次方-9n(x+y)的平方=3（x+y）²（4mx+4my-3n）如果本题有什么不明白可以追问,

1、(x的n次方+y的n次方)（x的n次方-y的n次方）-（x的n次方+y的n次方）²=(x^n+y^n)(x^n-y^n)-(x^n+y^n)^2=(x^n)^2-(y^n)^2-[x^(

(2x+3y+m)(x-y+n)=2x^2-3y^2+xy+(2n+m)x+(3n-m)y-mn同位相系数相等2n+m=-13n-m=-1得n=-2/5m=-1/5m+n=-3/5

3a(x-y)m²+12a(y-x)n²=3a(x-y)m²-12a(x-y)n²=3a(x-y)(m²-4n²)=3a(x-y)[m

m+2的算术平方根+|n-4|=0由题意可知m=-2,n=4代入原方程得：（4-8y）-(x²+y²)=-y²-8y-16-x²+20=-(y+4)²

原式=(m³+n²)²原式=[2(x+y)-(x-y)]²=(x+3y)²

2x^n-6x^(n-1)-8x^(n-2)=2x^(n-2)(x^2-3x-4)=2x^(n-2)(x-4)(x+1)

/>1.a(x+y)-b(x+y)=(x+y)(a-b)2.m(a-b)-n(b-a)=m(a-b)+n(a-b)=(a-b)(m+n)

公因式是mn(x-y)^n所以原式=mn(x-y)^n(n-m)两项中m最低是1次,n最低原式1次而x-y是n和n+1次,则最低是n次所以公因式是mn(x原式=mn(x-y)^n*(-m)mn(x-y

-2my-2ny

(x²+y²)(x+y)(x-y)=x^4-y^4n=4

题中说他俩的绝对值互为相反数,而我们又知一个数的绝对值必为正数,且又知0的绝对值0.所以由题得|m+4|=|n^-2n+1|=0可得m=-4,n=1.则有(x^+4y^)-(-4xy+1)=x^+4y

楼主看一下是不是打错符号了?(m-n)²-2(m-n)(x-y)＋(x-y)²=[(m-n)-(x-y)]²=(m-n-x＋y)²(m-n)²-2(m

6x的n+1次方+5x的n次方y-4x的n-1次方y²=x^(n-1)(6x^2+5xy-4y^2)=x^(n-1)(2x-y)(3x+4y)