x-1分之x (x-x分之1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/09 10:25:49
解原式=x-1分之x的平方-x-1=x-1分之x(x-1)-1=x-1
原式=(x²+x-2x)/(x+1)÷[(x-1)²/(x+1)(x-1)]=(x²-x)/(x+1)÷[(x-1)/(x+1)]=x(x-1)/(x+1)*(x+1)/
原式得:1/(x-3)=2-x/(x-3)两边同时乘以x-3得:2x-6-x=1x-6=1x=7
原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x+3)(x+5)]\(x^2+7x+13)=[(1分之x+2)-(1分之x+3)+(1分之x+
3/(x+1)-3x/(x+1)?=(3-3x)/(x+1)=3(1-x)/(1+x)再问:(x-1)的平方分之三-(x-1)的平方分之3x再答:3/(x-1)^2-3x/(x-1)^2=(3-3x)
=2x/x²-(2x-1)/x²=(2x-2x+1)/x²=1/x²
步步高点读机哪里不会点哪里
(x/2)+(x/6)+(x/12)+(x/20)+(x/30)+(x/42)=x/(1*2)+x/(2*3)+x/(3*4)+x/(4*5)+x/(5*6)+x/(6*7)=x-x/2+x/2-x/
这个是用等比、等差做的再问:根据n(n+1)分之1=n分之1-n+1分之1的规律化简再答:对--到最后--中间的都消去。只省最前和最后的---自己看看高中书中的这张-我也好久没看了,快记不得了-再问:
(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)=(x²-x-6+x-3)/x(x-3)=
=[(x+2)/x(x-2)-(x-1)/(x-2)²]×x/(4-x)=[(x²-4-x²+4)/x(x-2)²]×x/(4-x)=1/(x-2)²
=x/(x+2)(x-2)-(x-2)/(x+2)(x-2)=[x-(x-2)]/(x+2)(x-2)=2/(x²-4)
①X平方+2X分之X+2-X平方-4X+4分之X-1=(x+2)/x(x+2)-(x-1)/(x-2)²=[(x-2)²-x²+x]/x(x-2)²;=(4-3
再问:再答:
x²/(x-1)+x/(1-x)=x²/(x-1)-x/-(1-x)=x²/(x-1)-x/(x-1)=x²-x/(x-1)=x(x-1)/(x-1)=x
7/x(x+1)-6/(x+1)(x-1)=-1/x(x-1)两边乘以x(x+1)(x-1)得7(x-1)-6x=-(x+1)7x-7-6x=-x-12x=6∴x=3经检验:x=3是方程的解
(x+1)/(x+2)-1/(x+7)=(x+2)/(x+3)-1/(X+6)(X+2-1)/(X+2)-1/(X+7)=(X+3-1)/(X+3)-1/(X+6)1-1/(X+2)-1/(X+7)=
2x/(x+1)+1/x=2(2x^2+x+1)/x(x+1)=22x^2+x+1=2x(x+1)2x^2+x+1=2x^2+2xx=1
原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]÷(4-x)/x=[(x+2)(x-2)/x(x-2)²-x(x-1)/x(x-2)²]÷(4-x)/x=[(