x-2分之2x-6除以x²-4x+4分之x-3
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/23 02:23:56
原式=[(x²+2x)/(x²+4x+4)]÷[(2x²-8)/(3x+6)]÷[1/(x²-4)]=[x(x+2)/(x+2)²]÷{2(x+2)(
原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]*x/(x-1)(x-4)*(x-2)²=(x²-4-x²+x)/x(x-2)²*x/(x
①3除以x分之2=3*x/2=3x/2②x分之3除以x^2分之6=3/x*x^2/6=x/2③x分之2x+1除以5分之6+12x=(2x+1)/x*5/(6+12x)=5/6x④x^2+3x+2分之x
原式=[√(x/4)-2x√(1/x)]÷3√x=√(x/4)÷3√x-2x√(1/x)÷3√x=(1÷3)×√(x/4÷x)-(2x÷3)×√(1/x÷x)=1/3×√(1/4)-(2x/3)×√(
把平方代入根号除以根号得出{3根号X-2根号X}除以3根号X=根号X除以3根号X=3分之1
x^2-x-6分解因式得(x+2)(x-3)x^2-4分解因式得(x-2)(x+2)故(x^2-x-6分之x^2-4+x-3分之x+2)=(x-2)/(x-3)+(x+2)/(x-3)=2x/(x-3
原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x+3)(x+5)]\(x^2+7x+13)=[(1分之x+2)-(1分之x+3)+(1分之x+
x平方-4x+4分之2x-6除以(x+3)=(2x-6)/(x²-4x+4)÷(x+3)=2(x-3)/(x-2)²×1/(x+3)=2(x-3)/(x+3)(x-2)²
再问:�ף���Ŀ��������再问:再答:再问:лл��再问:����������再答:����再问:лл再问:再答:再问:лл再问:�㼸�꼶��再问:˯û
(x-3)/(2x+4)÷(5-x-2)/(x-2)=(x-3)/[2(x+2)]×(x-2)/(3-x)=(x-3)/[2(x+2)]×-(x-2)/-(3-x)=1/2
答:6/x=(1/2)/(1/5)6/x=5/25x=12x=12/5经检验,是原分式方程的根0.2/25=4/x所以:0.2x=4*250.2x=100x=500经检验,是原分式方程的根
原式=(x-1)/(x-2)÷(x-1)²/(x+2)(x-2)=(x-1)/(x-2)*(x+2)(x-2)/(x-1)²=(x+2)/(x-1)
4-4x+x^2分之2x-6除以(x+3)乘以3-x分之x^2+x-6=2(x-3)/(x-2)²×1/(x+3)×(x+3)(x-2)/(3-x)=-2/(x-2)
2x分之(x+2)*(x^2+5x+6)分之(x^3-3x^2)÷(x^2+2x-3)分之(x^3-9x)=2x分之(x+2)*(x+2)(x+3)分之x^2(x-3)*x(x+3)(x-3)分之(x
2x-4分之3-x除以[x+2-x-2分之5]=(3-x)/(2x-4)÷[(x+2)-5/(x-2)]=(3-x)/2(x-2)÷(x²-4-5)/(x-2)=(3-x)/(x²
(x2-4x+x2/4-4+x+(2-x)/2)/(x/x-2)=(5/4x2-3x-4+(2-x)/2)/(x/x-2)=1/4(5x2-12x-16+4-2x)/(x/x-2)=(5x2-14x-
[(x^2-x-6)/(x^2-4)+(x-3)/(x+2)]÷(x-3)/(x+1)=[(x-3)(x+2)/(x-2)(x+2)+(x-3)/(x+2)]÷(x-3)/(x+1)=[(x-3)/(
请填写邀请码1766658,再问:?
数学之美团为你解答(x²-2x)/(x²-4)÷[x-2-(2x-4)/(x+2)]=x(x-2)/[(x+2)(x-2)]÷[(x²-4)/(x+2)-(2x-4)/(