x2-2xy-3y2 3x-5y 2=

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x2-2xy-3y2 3x-5y 2=
已知x2+y2=9,xy=-3,求多项式5x²-3xy-5y²-11xy-8x²+2y&#

5x²-3xy-5y²-11xy-8x²+2y²=-3x²-3y²-14xy=-3(x²+y²)-14xy=-3x9+1

已知x2-2xy=3y2且x,y为非零实数 求:(1)2x+y/x-2y (2)2x2-3y2+5xy/x2+xy+y2

∵x²-2xy-3y²=0∴*(x-3y)(x+y)=0∴x=3y或x=-y(1)2x+y/x-2y当x=3y时,原式=7y/y=7当x=-y时,原式=y/(-3y)=-1/3(2

2x2+xy-y2-5x+4y-3如何因式分解?

2x"+xy-y"-5x+4y-3=2x"+2xy-xy-y"-6x+x+y+3y-3=2x(x+y)-y(x+y)+(x+y)-6x+3y-3=(x+y)(2x-y+1)-3(2x-y+1)=(x+

x2-xy-2y2-x+5y-2

首先,X^2-XY+2Y^2=(X-2Y)(X+Y)所以,设x^2-xy-2y^2-x+5y-2可分解成(X-2Y+A)(X+Y+B)则展开有X的一次项=A+B=-1Y的一次项有A-2B=5连列成方程

已知x+y=4,xy=2,则x2+y2+3xy=______.

x2+y2+3xy=(x+y)2+xy,∵x+y=4,xy=2,∴x2+y2+3xy=42+2=18.故答案为18.

(8xy-3x2)-5xy-3(xy-2x2+3)

A=-6-4+2+1=-7,B=6+4-2+1=9A-2B=-7-2x9=-25

分解因式:x2+3xy+2y2+4x+5y+3.

∵x2+3xy+2y2=(x+2y)(x+y),x2+4x+3=(x+1)(x+3),2y2+5y+3=(2y+3)(y+1),∴x2+3xy+2y2+4x+5y+3=(x+2y+3)(x+y+1).

x2-2xy+y2+3x-3y+2.

x2-2xy+y2+3x-3y+2=(x-y)2+3(x-y)+2=(x-y-1)(x-y-2).

已知x+y=4,xy=2,求x2+y2+3xy的值.

∵x+y=4,xy=2,∴x2+y2+3xy,=(x+y)2+xy,=42+2,=18.

已知2x2+5xy-3y2=0且xy不等于0,求x:y的值

2x2+5xy-3y2=0(2X-Y)(X+3Y)=0==>X=Y或者X=-3YXY不等于0,即X,Y都不等于0所以X:Y=X/Y=1或者-1/3

约分 xy+2y/x2次方-4

y(x+2)/(x-2)(x+2)=y/(x-2)提取yx²-4=(x-2)(x+2)

先化简,后求值:4xy-(2x2+5xy-y2)+2(x2+3xy),其中|x+2|+(y−12)

4xy-(2x2+5xy-y2)+2(x2+3xy),=4xy-2x2-5xy+y2+2x2+6xy),=5xy+y2,∵.x+2  .+(y-12)2=0∴x=-2,y=12当x

已知:x=3,y=-5,x2-2xy+y2/x2-y2的值是

x²-2xy+y²/x²-y²=(x-y)²/(x-y)(x+y)=(x-y)/(x+y)因为x=3,y=-5,所以(3-(-5))/(3+(-5))

问:因式分解2x2-3xy+y2+5x-y-2

题目可能是2x2-3xy+y2+5x-y-12吧!2x2-3xy+y2+5x-y-12=(2x-y-3)(x-y+4)

已知x2;+xy=3,xy+y=-2,求代数式2x2;-xy-3y2;的值

2x²-xy-3y²=2x²+2xy-3xy-3y²=2(x²+xy)-3(xy+y²)已知x²+xy=3,xy+y²=

计算:12xy+(3x2-5xy)-2(3xy+2x2).

原式=12xy+3x2-5xy-6xy-4x2,=xy-x2.

2x2+xy-3y2+x+4y-1因式分解

2x²+xy-3y²+x+4y-1=2×x×x+x×y-3×y×y+x+4×y-1=x×2x+x×y-y×3y+x×1+y×4-1=x×(2x+y+1)-y×(3y+4)-1再问:

x2-xy-2y2-x+5y-2因式分解

首先,X^2-XY+2Y^2=(X-2Y)(X+Y)所以,设x^2-xy-2y^2-x+5y-2可分解成(X-2Y+A)(X+Y+B)则展开有X的一次项=A+B=-1Y的一次项有A-2B=5连列成方程

先化简再求值2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)],其中x=-1,y=-2.

原式=2x2-2xy-6x2+9xy-2x2+2x2-xy+y2=-2x2+5xy+2y2,当x=-1,y=-2时,原式=-2+10+8=16.