x^2y x^2< y

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x^2y x^2< y
[(x+y)(x-y)-(x-y)的平方+2y(x-y)]除以(4y)请帮我一下写两道计算题

1、=(x²-y²-x²+2xy-y²+2xy-2y²)÷(4y)=(4xy-4y²)÷4y=x-y2、=(9x²-4y²

x^2-y^2/x+y-4x(x-y)+y^2/2x-y,

(x^2-y^2)/(x+y)-(4x(x-y)+y^2)/(2x-y)=(x-y)(x+y)/(x+y)-(4x^2-4xy+y^2)/(2x-y)=(x-y)-(2x-y)^2/(2x-y)=(x

计算:(x-y)^2*(y-x)^2*(x-y)^6

(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x

1、x(x-y)(x+y)-x(x+y)^2

1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)(2a+b)(2

【(x-y)^2+(x+y)(x-y)】除以 2x

【(x-y)^2+(x+y)(x-y)】除以2x=(x-y)*(x-y+x+y)/2x=(x-y)*2x/2x=x-y

[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y

[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y=[x²-y²-x²-2xy-y²-xy+xy²]/(y/2)=[(x-2)y

6(x+y)2-2(x-y)(x+y)因式分解

(x+y)ˆ2-2(x+y)(x-y)+(x-y)ˆ2=(x+y-x+y)^2=(2y)^4=4y^2如果满意请点击右上角评价点【满意】即可~再问:这个我看不懂,能不能写下来啊,谢

帮因式分解谢谢,4(x+y)(x-y)^3-9(x+y)^3(x-y) 9x^2-x+1/16这两题,

4(x+y)(x-y)^3-9(x+y)^3(x-y)=(x+y)(x-y)[4(x-y)²-9(x+y)²]=(x+y)(x-y){[2(x-y)]²-[3(x+y)]

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方

(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方=x²-2xy-3y²-x²+4y²-x²+2xy-y²=(x²-

2x分之1减x+y分之1×(2x分之x+y-x-y)帮我,

原式=1/2x-1/(x+y)[(x+y)/2x-(x+y)]=1/2x-(1/2x-1)=1/2x-1/2x+1=1

(2x-y)^2-4(x-y)(x+2y)

4x^2+y^2-4xy-4(x^2-xy+2xy-2y^2)展开化简吧!

[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)

=(x-y)[(3x+y)-(2x+3y)]*(x-y)=(x-y)*(x-y)(3x+y-2x-3y)=(x-y)(x-y)(x-2y)到底是化简,还是?=(x*x-2xy+y*y)(x-2y)=x

(1)(x^2/x)-y-x-y

(1)x^2/x)-y-x-y=x-y-x-y=-2y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)=a(a+b-a+b)/(a^2-b^2)-(2b^2/a^2-b^2)=2b/

【x-3y][x+y]-[x-2y][x +2y]-[x-y

解题思路:根据题意,由整式的运算的知识整理,分析可以求得解题过程:

有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-

解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!

谁帮我化简:[(x+y)(x-y)-(x+y)^2-2y(x-y)-2xy]÷xy

原式=(x^2-y^2-x^2-2xy-y^2-2xy+2y^2-2xy)/xy=(-6xy)/xy=-6

(x+y)^2(x-y)^2-(x-y)(x+y)(x^2+y^2)分解因式

原式=(x+y)(x-y)[(x+y)(x-y)-(x²+y²)]=(x+y)(x-y)(x²-y²-x²-y²)=-2y²(x+

暑假作业因式分解(x+y-2xy)(x+y)+(xy-1)2

x+y-2XY)(x+y-2)+(xy-1)^2=[(x+y)-2xy][(x+y)-2]+(xy-1)^2=(x+y)^2-2(xy+1)(x+y)+4xy+x^2y^2-2xy+1=(x+y)^2