x^4 2x^3y 3x^2y^2 2xy^3 y^4的值
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[23x−2x+y(x+y3x−x−y)]÷x−yx=[23x−2x+y•x+y3x+2x+y•(x+y)]•xx−y=(23x−23x+2)•xx−y=2xx−y故答案为2xx−y.
3y^2=12y3y^2-12y=03y(y-4)=0y1=0,y2=43x^2-5x=0x(3x-5)=0x1=0,x2=5/3(x+3)^2=2x(x+3)x^2+6x+9=2x^2+6xx^2=
(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.(x+y)^2-(x+y)^3=(x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、(x
写清楚点点比如说前面是X/X还是X/(X-Y)打上括号分段这样才能清楚的做
(x+y)(x+y)^2(-x-y)^3=-(x+y)^6
解方程组2x−5=y,①3x−2y=12,②时,把①代入②即可消去y,达到消元的目的;解方程组2x+3y=133x−4y=−6时,想法把y的系数化为相同,然后用减法化去,达到消元的目的.故答案是:代入
3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)
y的平方+4=6Y公式B平方-4乘A乘CA=1B=-6C=4《A为2次项系数.》即:36-16=20Y=《-B+-根号B平方-4乘A乘C》除以2A最后Y=3+2倍根号5和3—2倍根号5
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
(-x-2y)*(3x-y)=-3x^2-5xy+2y^2
(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-(x-y)^(5+3+2)=-(x-y)^10
(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方=x²-2xy-3y²-x²+4y²-x²+2xy-y²=(x²-
=(x-y)[(3x+y)-(2x+3y)]*(x-y)=(x-y)*(x-y)(3x+y-2x-3y)=(x-y)(x-y)(x-2y)到底是化简,还是?=(x*x-2xy+y*y)(x-2y)=x
1.15-9y-9x>-9/43.3(x-1)-x+1212x>32X>8/3
解题思路:根据题意,由整式的运算的知识整理,分析可以求得解题过程:
解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!
[23x-2x+y(x+y3x-x-y)]÷x−yx=(23x-23x+2)×xx−y=2xx−y,∵5x+3y=0,∴y=-53x,∴原式=2xx+53x=34.
[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)=[x²y(xy-1)-yx&sup
(x+y)^2-3(x+y)=(x+y)(x+y-3)