x² xy-2y²-3x-12y-10分解因式-搜答案-大师作文网

原式=x²-y²-(4x²y²+12xy²+9y²)=x²-y²-4x²y²-12xy²-

x^2-xy-6y^2+3xy+y+2

3xy是3x原式=(x-3y)(x+2y)+3x+y+2十字相乘x-3y2×x+2y1所以原式=(x-3y+2)(x+2y+1)

对.前提是x不等于y

3xy[2xy-x(y-2)+x-1]=3xy(2xy-xy+2x+x-1)=3xy(xy+3x-1)=3x^2y^2+9x^2y-3xy

3xy[2xy-x（y-2）+x]＝3xy[2xy-xy+2x+x]=3xy(xy+3x)=3x²y²+9x²y

(3xy)平方/(-xy)+(x-2y)平方-(x+2y)(x-2y)=-9xy+(x-2y)(x-2y-x-2y)=-9xy+(x-2y)(-4y)=-9xy-4xy+8y²=8y

-12xy*3x^2y-x^2y*(-3xy)

-12xy*3x^2y-x^2y*(-3xy)=-36x^3y^2+6x^3y^2=-30x^3y^2

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

x^3+x^2y-xy^2-y^3=（x-y）(x^2+xy+y^2)+xy(x-y)=(x-y)(x^2+y^2+2xy)=(x-y)(x+y)^2

我的回答满意吗?再答：再答：望采纳！再答：图片正在发送再答：发过去了再答：看不懂可以问我

【x²+xy/（x-y）】/【xy/（x-y）】=【x²（x-y）/（x-y）+xy/（x-y）】/【xy/（x-y）】={【x²（x-y）+xy】/（x-y）}/【xy

符号好像有问题.x³+x²y-xy²-y³=x²(x+y)-y²(x+y)=(x+y)(x²-y²)=(x-y)(x+y

（4xy+12y)+[7x-(3xy+4y-x)]=4xy+12y+7x-3xy-4y+x=xy+8x+8y=xy+8(x+y)=(-2)+8*3=-2+24=22

x^3y+2x^2y^3+xy^3

x^3y+2x^2y^3+xy^3=xy(x^2+2xy+y^2)=xy(x+y)^2再问：公式法——完全平方再答：对，第一步提取公因式

[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/

[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)=[x²y(xy-1)-yx&sup

1、(-7x^y)(2x^y-3xy^3+xy)=-14x^(2y)+21x^(y+1)y^3-7x^(y+1)y;2、((x-y)^6)/((y-x)^3)/(x-y)=-(x-y)^3/(x-y)

x²y+3xy²-x-3y=xy(x+3y)-(x+3y)=(x+3y)(xy-1)

原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&

-x³y³-x²y²-xy=-xy(x²y²+xy+1)