x加y等于五 xy等于负二 y分之x加x分之y等于多少六年级级解法
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xy分之x加y等于2∴x+y=2xy3x减5xy加3y分之负x加3xy减y=[-(x+y)+3xy]/[3(x+y)-5xy]=(-2xy+3xy)/(6xy-5xy)=xy/(xy)=1
x-y=-2①x+y=1②把①+②得x-y+x+y=-2+12x=-1x=-1/2把x=-1/2代入②得(-1/2)+y=1y=1-(-1/2)=3/2∴x=-1/2,y=3/2即x=-0.5,y=1
1/x-1/y=2(-x+xy+y)/(2x+7xy-2y)=(-x+xy+y)÷xy/(2x+7xy-2y)÷xy=(-1/y+1+1/x)/(2/y+7-2/x)=(1/x-1/y+1)/[-2(
x分之x的绝对值加y分之y的绝对值等于0所以x与y异号,即xy再问:没听懂再答:1.x0x分之x的绝对值加y分之y的绝对值=-1+1=02.x>0,y
X²+y²-2x+4y+5=0(x²-2x+1)+(y²+4y+4)=0(x-1)²+(y+2)²=0∴{x-1=0y+2=0∴x=1,y=
x等于0y等于2.5xy等于0..
稍等再问:在再答:正在做再答:不好意思再问:哦再答:x-4yx=-4yx-4xy+4y=0(x-2y)=0∴x-2y=0∴x=2y∴原式=(2y+4y)/(2y+y)=6/3=2再答:懂了吗再问:ok
-5(根号2)/2
已知x+y=-5,xy=2求√x/y+√y/x√x/y+√y/x=1/y√(xy)+1/x√(xy)=√(xy)(1/y+1/x)=√(xy)[(y+x)/xy]=√2*(-5)/2=(-5√2)/2
原式=5x-3y-2xy-6x-5y+2xy=-x-8y把x=-5,y=-1代入得原式=5+8=13
等22,整体带入再问:怎么代入再答:3x(-2)+10y+5x-2x(-2)-2y+3x=-2+8(y+x)=-2+24=22
x/y+y/x=(x²+y²)/xyx²+y²=(x+y)²-2xy=36-16=20原式=20/8=2.5
参考例题:已知关于xy的方程组x-2y=m,2x+3y=2m+4的解满足不等式组3x+y≤0,x+5y>0求满足条件的m的整数值第一个方程两边同乘以2得2x-4y=2m,减第二个方程得-7y=-4,所
已知xy/(x+y)=2,求:(3x-5xy+3y)/(-x+3xy-y)xy/(x+y)=2得:xy=2(x+y)(3x-5xy+3y)/(-x+3xy-y)=(3x-9xy+3y+4xy)/(-x
y=5/(x²-2x+2)令t=x²-2x+2=(x-1)²+1>=1所以0
xy分之【x加y】等于2分之一xy=2(x+y)【xy加x加y】分之xy=2(x+y)/[2(x+y)+x+y]=2(x+y)/[3(x+y)]=2/3
根据(x+y)2=x2+y2+2xy,可得x2+y2=13
1/x+1/y=-1/(x+y)两边同时乘x+y得1+y/x+1+x/y=-1所以y/x+x/y=-3