x平方加xy加y方等于a方求面积
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3x^2+2xy+y^2-6x-6y+9=0(x+y)^2-6(x+y)+9=0(x+y-3)^2=0x+y=3
x^2+y^2-4x-10y+29=0x^2-4x+4+y^2-10y+25=0(x-2)^2+(y-5)^2=0x=2y=5x^y+xy^2=xy(x+y)=2*5(2+5)=70
x²+xy-2y²=0﹙x-y﹚﹙x+2y﹚=0x=y,x=-2y当x=y,﹙x²+3xy+y²﹚/﹙x²+y²﹚=﹙y²+3y&
已知x平方加xy等于8,y平方加xy等于9,则x平方加y平方加2xy值是8+9=17
√(x-4y)=4x-4y=4的2次方x-4y=16(1)(3x+5y)的3次方=-273x+5y=-3(2)(2)-(1)×3得3x+5y-3(x-4y)=-3-16×33x+5y-3x+12y=-
x³-2x²y+xy²=x(x²-2xy+y²)=x(x-y)²
∵x+y-4x+y+4+1/4=(x-4x+4)+(y+y+1/4)=(x-2)+(y+1/2)=0而要使两个非负数的和为0,那么这两个数均为0∴x-2=0,y+1/2=0∴x=2,y=-1/2∴原式
6,or-7二式相加,设u=x+y,u^2+u=42u=6,u=-7再问:什么是二式相加
x³+x²y+xy²+y³=x²(x+y)+y²(x+y)=(x+y)(x²+y²)
x²+2xy+4y²+x²y²+1=8xy(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²
x+y=6xy=-21/x²+1/y²=(x²+y²)/(x²y²)=[(x+y)²-2xy]/(xy)²=(36+4)
先分解因式,后乘法.(X^4-Y^4)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X+Y)(X^2+Y^2)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X^3+X^2Y+XY^2+
x²+xy+y=14①y²+xy+x=22②①+②得:﹙x+y﹚²+﹙x+y﹚-36=0x+y=﹙﹣1±√145﹚/2.再问:最后一步怎么得来的没有看懂再答:一元二次方程
解题思路:此题主要考查了完全平方公式的应用;解答时整体求解xy解题过程:解:∵x+y=6∴(x+y)2=36即:x2+2xy+y2=36∵x2+y2=12∴12+2xy=3
原式等于(xy)^2(x+y)将x+y=2,xy=4代入,得原式等于16×2=32
x^2+2xy+y^2=(x^2+xy)+(xy+y^2)=2+7=9
x^2+2xy+y^2=(x^2+xy)+(xy+y^2)=2+7=9
x³-y³-x²y+xy²=(x³-y³)-(x²y-xy²)=(x-y)(x²+xy+y²)-xy