x的三次 y,-x的五次 y的二次~~~~的规律
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解x^2+Y^2=X+Y配方为(x-1/2)^2+(Y-1/2)^2=1即(X,Y)的到(2,1半)作为原点该圆的半径的根的SOx=1+成本*(半)^二分之一Y=1/2+SINT*(半)^二分之一吨任
原式=-(y-x)³x(y-x)²x(y-x)^2=-(y-x)^7再问:
(x-y)^5/[(y-x)^3(y-x)^2]=(x-y)^5/[-(x-y)^3(x-y)^2]=(x-y)^5/[-(x-y)^5]=-1.
(x-y)³×(x-y)²×(y-x)=(x-y)³×(x-y)²×[-(x-y)]=-(x-y)的6次方
第一题x/2+y/3=1(1)x-y=5(2)整理(1)得:3x+2y=6(3)(2)×2+(3)得:5x=16x=16/5把x=16/5代入(2)得:y=x-5=16/5-5=-9/5所以,原方程组
x³+y³=(x+y)(x²-xy+y²)=x²-xy+y²=(x+y)²-3xy=1-3xy=1/3∴xy=2/9x五次方+y五
(x-y)²(y-x)³(x-y)=(x-y)²[-(x-y)³](x-y)=-(x-y)的(2+3+1)次方=-(x-y)的6次方很高兴为您解答,【学习宝典】
(m-4)X^(|m|-2)Y^3+3X^2Y^2是五次二项式,|m|-2=2且m-4≠0∴m=-4再问:1,写出2个-3X的二次方Y的5次方的同类项2,多项式X的2次方-2X的二次方Y的二次方+3Y
-xy(x^2y^5-xy^3-y)=x^2y^4+xy^2-x^3y^6=(xy^2)^2+xy^2-(xy^2)^3
解(x-y)(y-x)²(x-y)³=(x-y)(x-y)²(x-y)³=(x-y)^6
原式=8x^5y²/(-2x²y)-4x²y^5/(-2x²y)=-4x³y+2y³
x+y的三次方*x+y的二次方=(x+y)^3(x+y)^2=(x+y)^(3+2)=(x+y)^5
(x--y)^3*(y--x)^2*(y--x))^5=--(x--y)^10.
原式=-(x+y)²×(x-y)²=-(x²-y²)²
x^3+x-y^3-y=(x^3-y^3)+(x-y)=(x-y)(x^2+xy+y^2)+(x-y)=(x-y)(x^2+xy+y^2+1).x^3-x^2-y^3+y^2=(x^3-y^3)-(x
(x-y)的五次方÷(y-x)的三次方=-(x-y)的五次方÷(x-y)的三次方=-(x-y)²
-(x-y)^10那位错了吧如果有什么不懂的,欢迎继续问我来自“理科最强”团队
-3X的5次方Z再问:确定吗再答:这可以确定的,只要你没给错题