x的平方剪y的平方除以y减x的平方
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因为正数x,y满足x平方-y平方=2xy,所以(x^2-y^2)=2xy即1-(y/x)^2=2(y/x)(y/x)^2+2(y/x)-1=0y/x=[-2+√(4+4)]/2=-1+√2(因为x,y
原式=(x^3y^2-x^2y-x^2y+3x^3y^2)÷3x^2y=(4x^3y^2-2x^2y)÷3x^2y=4/3xy-2/3
1-(x-y)/(x+2y)÷(x²-y²)/(x+2y)²=1-(x-y)/(x+2y)×(x+2y)²/(x+y)(x-y)=1-(x+2y)/(x+y)=
x+7y=y-3xx+3x=y-7y4x=-6yx=3/2yx²=9/4y²(x²-y²)/(x²+y²)=(9/4y²-y
[(x+2y)的平方-(x+y)(x-y)-5y的平方]除以(2x)=(x²+4xy+4y²-x²+y²-5y²)÷2x=4xy÷2x=2y
x^2=x的平方‘/’为除以[(x+2y)^2-(x+y)(x-y)-5y^2]/(2x)=[(x^2+4xy+4y^2)-(x^2-y^2)-5y^2]/(2x)=[4xy]/(2x)=2y[(3x
【x的平方-2x】除以2y-xy=x(x-2)/[-y(x-2)]=-x/y
=(xy-x的平方)除以(x的平方-2xy+y的平方\xy)乘以(x-y\x的平方)=-x(x-y)×xy/(x-y)2×(x-y)/x2=-y再问:嗯
(x-y)的平方除以(x-y)的6次方=1/(x-y)的4次方
设y/x=k,则把y=kx代入原式整理得(k^2+1)x^2-4x+1=0.令△≥0,得k^2≤3.则(y/x)max=k最大值=根号3
用到求根公式再问:怎么解用一元二次方程公式法再答:再问:太给力了,你的回答完美解决了我的问题!
原式=9x⁴/16y²*2y/3x+x²/2y²*x/2y²=3x³/8y+x³/4y⁴=(3x³y
(x+y)y除以xy的平方=(x+y)÷xyx的平方+xy除以(x+y)的平方=x(x+y)÷除以(x+y)的平方=x/(x+y)x的平方-y的平方除以(x+y)的平方=(x+y))(x-y)÷(x+
解题思路:把分式的分子分母分解因式再根据法则进行计算,能约分的要先约分解题过程:答案见附件
[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x
原式=[(x+y)/(x-y)]^2*[2(x-y)/5(x+y)-[X/(x^2y^2)]/[x/(x+y)]=2/5-[x/(x^2y^2)]*[(X+y)/x]=2/5-(x^2y^2)/(x+
(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!
(x²+xy)/(x+y)²=x(x+y)/(x+y)²=x/(x+y)2xy/(x+y)²x/(x²-y²)∵最简公分母为:(x+y)
(x-y)的五次方除以(y-x)的平方除以(x-y)=(x-y)的平方再问:有详细的过程吗?再答:(x-y)的五次方除以(y-x)的平方除以(x-y)=(x-y)的(5-2-1)次方=(x-y)的平方