y=2x² 1因式分解-搜答案-大师作文网

xy+x+y+1因式分解

(x+1)(y+1)

4(x+y)^2-20(x+y-1)+5=4(x+y)^2-20(x+y)+20+5=4(x+y)^2-20(x+y)+25=[2(x+y)]^2-2*[2(x+y)]*5+5^2=[2(x+y)-5

9(x+y)^2-6(x+y)+1=【3(x+y)-1】²

是(2x-y)²-4x+2y+1原式=(2x-y)²-2(2x-y)+1=(2x-y-1)²

（x-1)²-2y(x-1)+y²=x²-2x+1-2xy+2y+y²=x²-2xy+y²-2x+2y+1=(x-y)²-2(x-

4（x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(y^2-4y+4)-2x(2-y)=(y-2)^2+2x(y-2)=(y-2)(2x+y-2)

1:(x^2-9y^2)-(x+3y)=（x+3y）（x-3y）-(x+3y)=(x+3y)(x-3y-1)提取公因式2：(a-b)^4-(b-a)^2=(a-b)^4-(a-b)^2=(a-b)^2

1-x-y+xy 因式分解

1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)

=x^2+2xy+y^2-2x-2y+1=(x+y)²-2(x+y)+1=(x+y-1)²

x^2y+xy^2=xy(x+y)

已知：x+y=1,xy=-1/2,利用因式分解求：x(x+y)(x-y)-(x+y)的平方的值.x(x+y)(x-y)-x(x+y)^2=x(x+y)(x-y-x-y)=x(x+y)(-2y)=-2x

因式分解xy-x-y+1

xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)

使用平方差公式原式=【（x+y）+（x-y）】【（x+y）-（x-y）】=2x乘以2y=4xy

原式=（3x+3y-1）（3x+3y+1）标准的十字相乘法.

(2X-Y)²-1(X-2Y)(X+2Y)=4x²-4xy+y²-(x²-4y²)=4x²-4xy+y²-x²+4y&#

(x+y)的平方+2(x+y)+1=(x+y)²+2×(x+y)×1+1²=(x+y+1）²

好像不能分解!看看原题?再问：原题是比较x^2+y^2+1与x+y+xy的大小。。。再答：x、y的关系或取值条件没有给出？用作差法比较x^2+y^2+1-(x+y+xy)=x^2-2xy+y^2+xy

25(x-y)^2-1因式分解

25(x-y)^2-1=﹝5(x-y)+1﹞﹝5(x-y)-1﹞

xy-x-y+1因式分解

(x-1)(y-1)

xy-x-y+1=x(y-1)-(y-1)=(x-1)(y-1)(xy-x-y+1)^2=(x-1)^2(y-1)^2